The midpoint for any segment/line when you're given the start and end point of the line as A=(x1,y1) and B=(x2,y2) is
( ((x1 + x2) /2), ((y1 + y2)/2) )
So here the point is
( (-2+6)/2), (-6+12)/2) )
= (2, 3)
So it's the second option
Answer:
The two lines of reflection are
and 
Step-by-step explanation:
I will attach a file with the graph of the rectangle and the lines of reflection.
We know that RSTU is a rectangle with vertices at
,
,
and 
The first step is to draw the vertices on the plane and them the rectangle.
The rectangle is a symmetrical figure. Therefore if we want to carry the rectangle onto itself using a line of reflection this line must goes through the centroid of the rectangle.
Given that we have a rectangle whose width is
and its length is
its centroid will be place at
.
Looking at the graph and using this information we find that the two lines of reflection are
and
.
Answer:
75,000
Step-by-step explanation:
I wish I were those kids
Where are the numbers or just this? We need numbers like 1 0 6