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Law Incorporation [45]
3 years ago
7

Can someone help me out?

Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0

Answer: factorise the equation 49x^2+70x+25

Step-by-step explanation:

49x^2+70x+25

(7x)^2+2*7x*5+(5)^2

(7x+5)(7x+5)

therefore the sides of the square are (7x+5)(7x+5)

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The lines represented by the equations y x = 2 and y = x<br> 2 are
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Answer: Parallel

Step-by-step explanation:

3 0
3 years ago
2/5 + k/4 = 9/10 (solve with work)
Alla [95]

The LCD of 2/5 + k/4 = 9/10 is 20. Applying this LCD, we get:


8 + 5k = 18. Subtracting 8 from both sides: 5k = 10. Then k = 10/5, or k = 2.

6 0
3 years ago
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What is the value of x in the figure below
Otrada [13]

Answer:

It is 118°

Step-by-step explanation:

because these are corresponding angles.

3 0
3 years ago
If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.
ira [324]
2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
7 0
3 years ago
Could 10.6\text{ cm}, 5.6\text{ cm},10.6 cm,5.6 cm,10, point, 6, space, c, m, comma, 5, point, 6, space, c, m, comma and 4.0\tex
vladimir1956 [14]

Since we know that triangle inequality theorem states that sum of any two sides of a triangle must be greater than third side.

Now let us see if it is true for our given side lengths.

10.6+5.6>4.0

16.2>4.0

Now let us try with another pair.

5.6+4.0>10.6

9.6

We can see that sum of 5.6 and 4 is less than 10.6. Therefore, 10.6 cm, 5.6 cm and 4.0 cm can not be side lengths of a triangle.

7 0
3 years ago
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