A) For both sets A and B, calculating the mean, range, and quartiles are a good way of measuring the center and spread. Using standard deviation may not be the best because we do not know whether the distributions are normal or not.
b) For set A, the lowest value is 63, while the highest is 86. An estimate for the mean, based on the average of these, is 74.5. Most of the 70+ values are below 74.5, so we may guess that the mean will be above the median.
For set B, the lowest is 63, while the maximum is 95. The estimated mean would be 79. But since there are more values on the 80+ and 90+ side, the median is likely to be higher than 79.
c) For set A, the mean is 74.79, while the median is 73, therefore the mean is above the median, and the prediction in part b is correct.
Answer:
Sine 3 books are for 60-
60/3
Rs20 (per book)
and 5 books for Rs 90-
90/5
Rs18 (per book)
Thus we can save 2Rs and 5 books for Rs 90 iscthe best buy
Answer:
15 boys
Step-by-step explanation:
The ratio is 5 : 12
The 12 part of the ratio relates to the students in the class, that is 36
Divide 36 by 12 to find the value of one part of the ratio
36 ÷ 12 = 3 ← value of 1 part of the ratio, thus
5 × 3 = 15 ← number of boys in class
