To start off, you should make each fraction have a common denominator.
2*3 = 6
3*2 = 6
The lowest common denominator is six.
so 3 3/6 + 2 2/6 = 5 5/6
Hopefully that helps!
If you would like to solve 2x + 5y = -13 and 3x - 4y = -8, you can do this using the following steps:
2x + 5y = -13 /*4
3x - 4y = -8 /*5
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8x + 20y = -52
15x - 20y = -40
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8x + 15x + 20y - 20y = -52 - 40
23x = -92
x = -92 / 23
x = -4
<span>3x - 4y = -8
</span>3 * (-4) - 4y = -8
-12 - 4y = -8
12 + 4y = 8
4y = 8 -12
4y = -4
y = -1
The correct result would be x = -4 and y = -1.
I would assume that you would subtract the 2 integrals from each other, the 13 and -3, which will give you 16, and the integral in between 2 to 6, the integral on the right, and then add 2 to 16 which would be 18, I believe that would be the answer.
Its factors would be
(x+2)*(x-1)*(x+0)
x^2 +x -2
x^3 + 0 + x^2 + 0 -2x +0
Equation: x^3 + x^2 -2x
f(2) = 8 + 4 -4
2x^3 + 2x^2 -4x +0
f(2) = 16 + 8 -8
3x^3 + 3x^2 -6x +0
f(2) = 24 +12 -12
4x^3 + 4x^2 -8x +0
f(2) = 32 +16 -16
So, the equation is:
4x^3 + 4x^2 -8x = 0
