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Maslowich
3 years ago
12

There are 100 students at a college who have taken a course in calculus, 110 who have taken a course in discrete mathematics, an

d 50 who have taken courses in both calculus and discrete mathematics. The number of students who have taken a course in either calculus or discrete mathematics is
Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

110 students

Step-by-step explanation:

The number of students who have only taken calculus is given by the number of students who have taken calculus minus the students who have taken both classes:

C =100 -50\\C= 50\ students

The number of students who have only taken discrete mathematics given by the number of students who have taken discrete mathematics minus the students who have taken both classes:

D =110 -50\\C= 60\ students

The number of students that have taken a course in either calculus or discrete mathematics is:

E = C+D = 50+60\\E= 110\ students

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Step-by-step explanation:

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Answer:

Below!

Step-by-step explanation:

Using Pythagoras theorem, I will solve all of the problems.

<h3>________________________________________________</h3>

<u>Question 9:</u>

  • 10² = 6² + x²
  • => 100 = 36 + x²
  • => 100 - 36 = x²
  • => 64 = x²
  • => x = 8
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<u>Question 10:</u>

  • 26² = 24² + x²
  • => 676 = 576 + x²
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<u>Question 11:</u>

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<u>Question 12:</u>

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<h3>________________________________________________</h3>

<u>Question 13:</u>

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First, let's solve for the variable x using Pythagoras theorem.

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Answers (Nearest tenth):

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<h3>________________________________________________</h3>

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