Move constant to other side
add 1
4c^2-8c=1
divide by 4 to make leading coeficient 1
c^2-2c=1/4
take 1/2 of linear coeficient and square it
-2/2=-1, (-1)^2=1
add that to both sides
c^2-2c+1=1/4+1
factor perfect squaer and add
(c-1)^2=5/4
square root both sides
c-1=+/-(√5)/2
add 1
c=1+/-(√5)/2
c=2.12 or -0.12
Step-by-step explanation:
I am sorry but please give detailed question
Answer:
?
Step-by-step explanation:
is there supposed to be a picture with this
Answer:
20.6
Step-by-step explanation:
Given data
J(-1, 5)
K(4, 5), and
L(4, -2)
Required
The perimeter of the traingle
Let us find the distance between the vertices
J(-1, 5) amd
K(4, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4+1)²+(5-5)²)
d=√5²
d= √25
d= 5
Let us find the distance between the vertices
K(4, 5), and
L(4, -2)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((4-4)²+(-2-5)²)
d=√-7²
d= √49
d= 7
Let us find the distance between the vertices
L(4, -2) and
J(-1, 5)
The expression for the distance between two coordinates is given as
d=√((x_2-x_1)²+(y_2-y_1)²)
substitute
d=√((-1-4)²+(5+2)²)
d=√-5²+7²
d= √25+49
d= √74
d=8.6
Hence the total length of the triangle is
=5+7+8.6
=20.6
