Answer:
The largest area enclosed is A = xy = 6 feet 
6 feet = 36 
Step-by-step explanation:
i) The perimeter of the area is 2(x + y) =24 ∴ x + y = 12 ∴ y = 12 - x
ii) The area of rectangle enclosed A = xy ⇒ A = x ( 12 - x) = 12x - 
iii) differentiating both sides of the equation in ii) we get
⇒ x = 6 feet
iv) Differentiating both sides of equation in iii) we get 
= -2
Therefore the area enclosed is maximum as the double derivative is negative
v) therefore for largest area enclosed x = 6 feet and y = 12 - 6 = 6 feet
vi) therefore the largest area enclosed is
A = xy = 6 feet 6 feet = 36
The opposite angles of an inscribe quadrilateral are supplementary.
angle P + angle R = 180
6x + 7 + 12x + 11 = 180
18x + 18 = 180
18x = 162
x = 9
Now we will substitute in the value of x to find angle P and R.
angle P = 6(9)+7 = 61
angle R = 12(9)+11 = 119
Now we will find the value of y.
angle Q + angle S = 180
10y + 7 + 3(3y + 7) = 180
10y + 7 + 9y + 21 = 180
19y + 28 = 180
19y = 152
y = 8
Now substitute in the value of y to find angle Q and S.
angle Q = 10(8)+7 = 87
angle S = 3(3*8+7) = 93
Hope this helps :)
So you can say that the weight of a koala here can be x.
So x * 1/8 = 2
2 being the chinchilla's weight and the 1/8 coming from the fact that the chinchilla weighs 1/8 of the weight of the koala.
So you can just divide both sides by 1/8 first.
x * 1/8 = 2
/ 1/8 / 1/8
Or,
x *1/8 * 8/1 = 2 * 8/1
x = 16
So the koala weighs 16 pounds.
The Solution:
GIven:
Required:
Substitute:
Take the square root of both sides:
Answer:
9 inches
