Answer:
Step-by-step explanation:
I think you have the question incomplete, and that this is the complete question
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
To do this, we can start my mirroring the equation.
x² + y² = (x + y)² - 2xy,
This helps us break down the power from 4 to 2, so that we have
(sin²a)² + (cos²a)² = (sin²a + cos²a) ² - 2(sin²a) (cos²a)
Recall from identity that
Sin²Φ + cos²Φ = 1, so therefore
(sin²a)² + (cos²a)² = 1² - 2(sin²a) (cos²a)
On expanding the power and the brackets, we find that we have the equation proved.
sin^4a + cos^4a = 1 - 2sin^2a.cos^2a
Answer:
8 people ordered ice cream
Step-by-step explanation:
28/7=4
4x2=8
<h3>
Answer: Choice B</h3>
With matrix subtraction, you simply subtract the corresponding values.
I like to think of it as if you had 2 buses. Each bus is a rectangle array of seats. Each seat would be a box where there's a number inside. Each seat is also labeled in a way so you can find it very quickly (eg: "seat C1" for row C, 1st seat on the very left). The rule is that you can only subtract values that are in the same seat between the two buses.
So in this case, we subtract the first upper left corner values 14 and 15 to get 14-15 = -1. The only answer that has this is choice B. So we can stop here if needed.
If we kept going then the other values would be...
row1,column2: P-R = -33-16 = -49
row1,column3: P-R = 28-(-24) = 52
row2,column1: P-R = 42-25 = 17
row2,column2: P-R = 35-(-30) = 65
row2,column3: P-R = -19-36 = -55
The values in bold correspond to the proper values shown in choice B.
As you can probably guess by now, matrix addition and subtraction is only possible if the two matrices are the same size (same number of rows, same number of columns). The matrices don't have to be square.
V=u+at
4=u+1a
2=u+2a
subtract
2=-a
a=-2
4=u-2
u=6
v=6-2t
or y=6-2x
or y=-2x+6
