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faust18 [17]
3 years ago
10

Transform x2 + 6x + 8 = 0 into the form (x − p)2 = q?

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
7 0
<span><span>Step 1<span>x2 + 6x + 8 + 1 = 0 + 1
</span></span><span><span>Step 2<span>x2 + 6x + 9 = 1
</span></span><span>Step 3<span>(x + 3)2 = 1
Your answer is (x +3)2 = 1
Hope I helped <3</span></span></span></span>
liraira [26]3 years ago
5 0
So hmmm x²+6x+8=0

alrite.. let's do some grouping now
( x² + 6x + [?]²) + 8 = 0

notice above, we have a missing fellow in order to get a perfect square trinomial... hmm who would that be?

let's take a peek at the middle guy of the trinomial.. 6x.. hmmm let's factor it, 2*3*x, wait a minute!  2 * 3 * x... we already have x² on the left-side, since the middle term is just 2 * the square root of the other two terms, that means that the guy on the right, our missing guy must be "3"

alrite, let's add 3² then, however, bear in mind that, all we're doing is borrowing from our very good friend Mr Zero, 0

so if we add 3², we also have to subtract 3², let's do so

(x² + 6x +3² - 3²) + 8 = 0

(x² + 6x +3²) + 8 - 3² = 0

(x+3)²=3² - 8

(x+3)² = 1
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