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lubasha [3.4K]
3 years ago
7

Amar keeps picking playing cards out of a standard deck of 52 cards in the hopes that he will

Mathematics
1 answer:
lapo4ka [179]3 years ago
4 0

Answer:

The required probability is, 0.78

Step-by-step explanation:

There are, (52 - 13) = 39 cards which are not spade

5 cards can be chosen from the deck of 52 cards in

^{52}{C}_{5}  ways

and out of these 5 choices, none of them will be spade in,

^{39}{C}_{5}  ways

So,

P(None of the chosen cards is spade)

= \frac {^{39}{C}_{5}}{^{52}{C}_{5}}

\simeq 0.22

Hence,

P(out of these 5 choices, at least one card is spade)

\simeq (1 - 0.22)

= 0.78

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What is the solution of 2x^2+8=x^2-16
AfilCa [17]

Answer:

x = -12

Step-by-step explanation:

2x^2 + 8 = x^2 - 16

2x + 2x + 8 = x + x - 16

4x + 8 = 2x - 16

-2x        -2x

2x + 8 = -16

      -8     -8

2x = -24

----   ------

2        2

x = -12

8 0
3 years ago
I need help with this problem please?
user100 [1]

Answer:

Step-by-step explanation:

If ΔABC ~ ΔPQR

\frac{PQ}{AB} =\frac{QR}{BC} = \frac{RP}{CA}

or

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3 years ago
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Answer:

x greater than and equal to -7

Step-by-step explanation:

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8 0
2 years ago
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pentagon [3]

9514 1404 393

Answer:

  A = {put, the, cake, in, basket}

  B = {is, the, cake, in, basket}

  C = {no, the, cake, in, basket}

  D = { }

Step-by-step explanation:

A = (A -B) ∪ (A∩B) ∪ (A∩C}

A = {put} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

A = {put, the, cake, in, basket}

__

B = (B -A) ∪ (B -C) ∪ (B∩A) ∪ (B∩C)

B = {is} ∪ {is} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

B = {is, the, cake, in, basket}

__

C = (C -B) ∪ (C∩A) ∪ (C∩B)

C = {no} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

C = {no, the, cake, in, basket}

__

D = { } . . . . not defined anywhere

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3 years ago
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lbvjy [14]
The answer is (x,y) —> (y,-x)
8 0
3 years ago
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