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2 years ago

Radical functions and rational exponents unit test

Mathematics

1 answer:

Anika [276]2 years ago

3 0

There are different kinds of test. The term, Radical functions and rational exponents is explained below.

<h3>What are Radical functions and rational exponents?</h3>

Radical expressions are known to be functions that has radicals present in them.

Radical functions are known to appear in a lot of forms, ranging simple and familiar to complicated forms. Radicals and fractional exponents are said to be different ways of showing the same stuff/thing.

Rational exponents is known also as fractional exponents. They are functions or an expressions that has exponents that are known to be rational numbers.

Learn more about Radical functions from

brainly.com/question/13430746

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This is due today, and I have no idea what I'm doing, please help if you know anything.

defon

Binomial distribution formula: P(x) = (n k) p^k * (1 - p)^n - k

a) Probability that four parts are defective = 0.01374

P(4 defective) = (25 4) (0.04)^4 * (0.96)^21

P(4 defective) = 0.01374

b) Probability that at least one part is defective = 0.6396

Find the probability that 0 parts are defective and subtract that probability from 1.

P(0 defective) = (25 0) (0.04)^0 * (0.96)^25

P(0 defective) = 0.3604

1 - 0.3604 = 0.6396

c) Probability that 25 parts are defective = approximately 0

P(25 defective) = (25 25) (0.04)^25 * (0.96)^0

P(25 defective) = approximately 0

d) Probability that at most 1 part is defective = 0.7358

Find the probability that 0 and 1 parts are defective and add them together.

P(0 defective) = 0.3604 (from above)

P(1 defective) = (25 1) (0.04)^1 * (0.96)^24

P(1 defective) = 0.3754

P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358

e) Mean = 1 | Standard Deviation = 0.9798

mean = n * p

mean = 25 * 0.04 = 1

stdev = $\sqrt{np(1-p)}$

stdev = $\sqrt{(25)(0.04)(1-0.04)}$ = 0.9798

Hope this helps!! :)

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