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3 years ago

Area of a square with the length of 100cm and a width of 2cm

Mathematics

2 answers:

Pepsi [2]3 years ago

6 0

Answer:

200cm squared

Step-by-step explanation:

Rashid [163]3 years ago

4 0

Answer:

200 $cm^{2}$

Step-by-step explanation:

the formula for working out the area is to multiply the length by the width.

so for this you would multiply 100 by 2 which gives you 200 cm squared

$100*2=200cm^{2}$

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Anna007 [38]

Answer:

The answer is Tangent.

Step-by-step explanation:

Given that Tangent Rule is tanθ = opposite/adjacent. In this question, opposite is 11, adjacent is x and θ is 21°.

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3 years ago

For a moving object, the force acting on the object varies directly with the objects acceleration. When the force of 63 N acts o

Serjik [45]

Answer:

49N

Step-by-step explanation:

Step one

Given

When the force of 63 N acts on a certain object

the acceleration of the object is 9/ms^2

Firstly, we need to calculate the mass m

F=ma-------1

m= F/a

m= 63/9

m= 7kg

Step two:

Also, if the acceleration of the object becomes 7 m/s^2

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2 years ago

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?

Margaret [11]

The second equation, its setup is correct

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3 years ago

The diagonals of this rhombus are 8 and 16 units long. Their intersection creates four right angles, two 4-unit-long segments, a

Roman55 [17]

Answer:

$64\ \text{sq. units}$

Step-by-step explanation:

Area of a rhombus is the product of the length of the diagonals divided by two.

Length of one diagonal is 8 units and the other diagonal is 16 units

Area is given by

$A=\dfrac{8\times 16}{2}\\\Rightarrow A=64\ \text{sq. units}$

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Another approach is the diagonals have created 4 triangles where the base and is height is either 4 units long or 8 units long so the area of the rhombus would be the area of the 4 triangles.

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