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3 years ago

Area of a square with the length of 100cm and a width of 2cm

Mathematics

2 answers:

Pepsi [2]3 years ago

6 0

Answer:

200cm squared

Step-by-step explanation:

Rashid [163]3 years ago

4 0

Answer:

200 $cm^{2}$

Step-by-step explanation:

the formula for working out the area is to multiply the length by the width.

so for this you would multiply 100 by 2 which gives you 200 cm squared

$100*2=200cm^{2}$

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Can someone help solve both of these? ASAP

zhuklara [117]

Question 4

$\sin 30^{\circ}=\frac{y}{14\sqrt{3}}\\\\\frac{1}{2}=\frac{y}{14\sqrt{3}}\\\\\boxed{y=7\sqrt{3}}\\\\\\\\\cos 30^{\circ}=\frac{x}{14\sqrt{3}}\\\\\frac{\sqrt{3}}{2}=\frac{x}{14\sqrt{3}}\\\\\boxed{x=21}$

Question 5

$\cos 45^{\circ}=\frac{x}{28}\\\\\frac{1}{\sqrt{2}}=\frac{x}{28}\\\\x=\frac{28}{\sqrt{2}}\\\\\boxed{x=14\sqrt{2}}\\\\\\\\\sin 45^{\circ}=\frac{y}{28}\\\\\frac{1}{\sqrt{2}}=\frac{y}{28}\\\\y=\frac{28}{\sqrt{2}}\\\\\boxed{y=14\sqrt{2}}$

7 0

2 years ago

Brian recorded the number of commercials played during two types of television shows: an educational documentary and a primetime

Sladkaya [172]

Answer:

$m(x)_A = 5.2$ --- Mean absolute deviation of educational documentary

$m(x)_B = 4.7$ --- Mean absolute deviation of prime time drama

Step-by-step explanation:

Given

$n = 10$

See attachment for table

Required

Determine the mean absolute deviation of each

Mean absolute deviation m(x) is calculated as:

$m(x) = \frac{1}{n}\sum |x - \mu|$

For Educational Documentary

First, calculate the mean

$\mu = \frac{\sum x}{n}$

So:

$\mu_A = \frac{26 + 28 + 30 + 18+27 + 18 + 20 +31+17+17}{10}$

$\mu_A = \frac{232}{10}$

$\mu_A = 23.2$

The mean absolute deviation is then calculated as:

$m(x)_A = \frac{1}{n}\sum |x - \mu_A|$

$m(x)_A = \frac{1}{10}(|26 -23.2| +|28 -23.2| +|30 -23.2| +|18 -23.2| +|27 -23.2| +|18 -23.2| +|20 -23.2| +|31 -23.2| +|17 -23.2| +|17 -23.2|)$

$m(x)_A = \frac{1}{10}(|2.8| +|4.8| +|6.8| +|-5.2| +|3.8| +|-5.2| +|-3.2| +|7.8| +|-6.2| +|-6.2|)$

$m(x)_A = \frac{1}{10}(2.8 +4.8 +6.8 +5.2 +3.8 +5.2 +3.2 +7.8 +6.2 +6.2)$

$m(x)_A = \frac{1}{10}*52$

$m(x)_A = 5.2$

For Prime time Drama

First, calculate the mean

$\mu = \frac{\sum x}{n}$

So:

$\mu_B = \frac{39+39+35+29+40+27+41+29+32+30}{10}$

$\mu_B = \frac{341}{10}$

$\mu_B = 34.1$

The mean absolute deviation is then calculated as:

$m(x)_B = \frac{1}{n}\sum |x - \mu_B|$

$m(x)_B = \frac{1}{10}(|39-34.1|+|39-34.1|+|35-34.1|+|29-34.1|+|40-34.1|+|27-34.1|+|41-34.1|+|29-34.1|+|32-34.1|+|30-34.1|)$

$m(x)_B = \frac{1}{10}(|4.9|+|4.9|+|0.9|+|-5.1|+|5.9|+|-7.1|+|6.9|+|-5.1|+|-2.1|+|-4.1|)$

$m(x)_B = \frac{1}{10}(4.9+4.9+0.9+5.1+5.9+7.1+6.9+5.1+2.1+4.1)$

$m(x)_B = \frac{1}{10}*47$

$m(x)_B = 4.7$

6 0

3 years ago

Tell wether the given value is a statistic or a parameter.

Agata [3.3K]

Answer:

$Statistic$

Explanation:

Here, we want to check if the given statement is a statistic or a parameter

While a parameter describes the whole population, a statistic describes a sample

From what we have in the question, the data completely describes each set of staff in the mathematics department

Thus, we can say it is a statistic

5 0

11 months ago

Help asap please and thanks

Arada [10]

He can only go as low as $500

7 0

3 years ago

Two of the vertices of a rectangle are (1, −6) and (−8, −6). If the rectangle has a perimeter of 26 units, what are the coordina

pantera1 [17]

Answer: $(x_1,y_1)=(1,-2)$

$(x_2,y_2)=(-8,-2)$

Step-by-step explanation:

Given

Co ordinates of vertices(1,-6) and (-8,-6)

When two points is given then Length of two points is given by

$L=\sqrt{\left ( x_2-x_1\right )^2+\left ( y_2-y_1\right )^2}$

$L=\sqrt{\left ( 1-\left ( -8\right )\right )^2+\left ( -6+6\right )^2}$

$L=\sqrt{9^2}=9 units$

Perimeter of rectangle is =26 units

Let the other side be x

thus

$2\left ( x+9\right )=26$

x+9=13

x=4 units

therefore to get the other two co ordinates

such that the length of that side is 4 units is

$(x_1,y_1)=(1,-2)$

$(x_2,y_2)=(-8,-2)$

Horizontal distance will remain same only vertical distance will change in given co ordinates to obtain the remaining two co ordinates

To verify the above two distance between two points must be 13 units

6 0

3 years ago