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avanturin [10]
3 years ago
5

Select the correct answer from each drop-down menu.

Mathematics
2 answers:
Gemiola [76]3 years ago
5 0

1.) is

2.) is not

3.) is not

4.) is

Luden [163]3 years ago
3 0

For this case we must indicate which of the points belongs to the shaded region shown in the figure.

Point A: (- 3,2)

It is observed that when plotting, the point is located in the second quadrant, within the shaded region.

Point B: (- 7,5)

It is observed that when plotting, the point is located in the second quadrant, just above the dotted line, which means that it does not belong to the shaded region.

Point C: (2, -5)

It is observed that when plotting, the point is located in the fourth quadrant outside the shaded region.

Point D: (-14,6)

It is observed that when plotting, the point is located in the second quadrant, within the shaded region.

Answer:

A. Belongs to the region (is)

B. Does not belong to the region (is not)

C. Does not belong to the region (is not)

D. Belongs to the region (is)

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Determine the projection of u=1.6i+3.3j in the v=-2.1i-0.5j direction
Lina20 [59]

The projection of \vec u onto \vec v is

\mathrm{proj}_{\vec v}(\vec u)=\dfrac{\vec u\cdot\vec v}{\vec v\cdot\vec v}\vec v

We have

\vec u\cdot\vec v=1.6\cdot(-2.1)+3.3\cdot(-0.5)=-5.01

\vec v\cdot\vec v=\|\vec v\|^2=(-2.1)^2+(-0.5)^2=4.66

\implies\mathrm{proj}_{\vec v}(\vec u)=\dfrac{-5.01}{4.66}\vec v\approx2.26\,\vec\imath+0.54\,\vec\jmath

8 0
4 years ago
1) The school that Lisa goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4
r-ruslan [8.4K]
A - price of the senior citizen ticket
b - price of the student ticket
{4a+5b=102
{7a+5b=126
3a=24 → a=8
5b=102-32
5b=70
b=14
price of the senior citizen ticket is $8
price of the student ticket is $14
8 0
3 years ago
How do you do this problem <br> X98=98,000
Butoxors [25]

Answer: The value of X is 1000

Step-by-step explanation:

X98 = 98,000 means a variable 'X' multiplied by 98 is equal to 98000

ie X x 98=98,000

To get the value of X, divide both sides by 98

X98/98 = 98,000/ 98

X = 1000

Thus, 1000 x 98 is truly equal to 98000

4 0
3 years ago
Scale the numerator and the denominator up by a factor of 5 (multiply) to write a
Dmitry_Shevchenko [17]

Answer:

15/50

Step-by-step explanation:

5*3=15

5*10=50

so 15/50.

4 0
3 years ago
Which equation have no real solution?
Ad libitum [116K]

To find out which equation has no real solutions, we need to calculate the discriminant for each of these given equations.

For calculating the discriminant, we need to first compare these equations with the general formula which is <u>ax²+bx+c.</u>

So, let's get started.

1) x² + 4x + 16 = 0

a=1, b=4, c=16

D = b²-4ac

= (4)² - 4(1)(16)

= 16-64

= -48

√D = √-48

2) 4x² + 4x - 24 = 0

a=4, b=4, c=-24

D = b²-4ac

= (4)² - 4(4)(-24)

= 16 - 16(-24)

= 16 + 384

= 400

√D = √400 = +20 or -20

3) 5x² + 3x - 1 = 0

a=5, b=3, c=-1

D = b²-4ac

= (3)² - 4(5)(-1)

= 9 + 20

= 29

√D = √29

4) 2x² - 4x + 4 = 0

a=2, b=-4, c=4

D = b²-4ac

= (-4)² - 4(2)(4)

= 16 - 32

= -16

√D = √-16

Now from all these above calculations, we can see that discriminant was negative in first equation and in last equation.

If D<0 then roots does not exist, as the square root can not contain a negative value or the equation does not have any real solutions.

Roots in such case can be calculated but those roots are known as imaginary roots, which is a higher concept.

So Final answer is,

Equation 1 => x² + 4x + 16 = 0

and

Equation 4 => 2x² - 4x + 4 = 0

has no real solutions.

4 0
4 years ago
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