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Orlov [11]
3 years ago
12

Find the x and y intercepts. Write your answer as x = y = 2x + 5y = 10

Mathematics
1 answer:
Ann [662]3 years ago
6 0
The x-intercept is present where y = 0

2x + 5y - 10 = 0
2x - 10 = -5y
2x - 10 = -5(0)
2x = 10
x = 5

The y-intercept is present where x = 0

2x + 5y = 10
2x + 5y - 10 = 0
5y - 10 = -2(0)
5y = 10
y = 2
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What is Q1 AND Q3 AND IQR OF THE NUMBERS<br>2,12,52,33,8,14
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If you invest $500 at 4% interest,compounded annually,how much is in the account at the end of six years?
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3 0
3 years ago
Need help!! I can't figure this out
Sidana [21]

9514 1404 393

Answer:

  12. $1,035,057.23

  13. $988,881.23

  14. $7,762.93

  15. $8,686.16

  16. $967,647.66

Step-by-step explanation:

The annuity and amortization formulas are used for problems like this.

  sum of monthly payments = P((1 +r/12)^(12t) -1)/(r/12)

  monthly amount available = P(r/12)/(1 -(1 +r/12)^(-12t))

__

12. The sum of monthly payments of 74, accumulated at 9% compounded monthly for 52 years is ...

  A = ($74)((1 +.09/12)^(12·52) -1)/(.09/12) = $1,035,057.23

__

13. The total of payments is ...

  $74×12×52 = $46,176

So, the interest earned is ...

  $1,035,057.23 -46,176 = $988,881.23

__

14. The amount available in perpetuity is the monthly interest on this account balance.

  $1,035,057.23 × .09/12 = $7,762.93

__

15. The monthly amount available for 25 years is found from the amortization formula:

  A = $1,035,057.23(.09/12)/(1 -(1 +.09/12)^(-12·25)) = $8686.16

__

16. The amortization formula is used for this, too.

  8066 = P(.094/12)/(1 -(1 +.094/12)^(-12·30)) = 0.00833568P

  P = $8066/0.00833568 = $967,647.66

7 0
2 years ago
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