Y=(kx)/z
15=(k10)/4
15=(5k/2)
15=k(5/2)
ties both sides by 2/5 to clear fraction
6=k
y=(6x)/z
x=20
z=6
y=(6*20)/6
y=20
Answer:
0.5
Step-by-step explanation:
Let D be the event of selecting a marble with dots.
Let P be the event of selecting a purple marble.
The probability of selecting a marble with dots, P(D)=0.2
The probability of selecting a marble that is both purple and has dots, 
We want to determine the probability of selecting a purple marble given that the marble has dots on it, P(P|D)
By the definition of conditional probability:

The probability of selecting a purple marble given that the marble has dots on it is 0.5.
<span>Answer: Skewed to right with mean 0 and S.D. 1
Explanation: Let's assume the z-scores as a linear transformation.
then z=(x-mean)/S.D. = (x-30)/15
z(mean) = (30-30)/15= 0
z(sigma) = 15/15 = 1
Note: Shape does not change.</span>
Step-by-step explanation:
Rhombus since the other 3 have lines that go accross the graph horizontally for 3 squares.
Answer:
The point of intersection
(0,-14,22/5), (2,0,24/5), (-22,-24,0).
Step-by-step explanation:
Check attachment for solution