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san4es73 [151]
3 years ago
12

How do I solve this?

Mathematics
1 answer:
Kryger [21]3 years ago
4 0
     y = abˣ
   20 = ab¹
   20 = ab
    b      b
20/b = a

 y = abˣ
 4 = (20/b)b²
 4 = 20b
20    20
¹/₅ = b

   y = abˣ
 20 = ¹/₅b¹
 20 = ¹/₅b
  ¹/₅     ¹/₅
100 = b

y = abˣ
y = 100(0.2)ˣ
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5.2.14. For the negative binomial pdf p (k; p, r) = k+r−1 (1 − p)kpr, find the maximum likelihood k estimator for p if r is know
Volgvan

Answer:

\hat p = \frac{r}{\bar x +r}

Step-by-step explanation:

A negative binomial random variable "is the number X of repeated trials to produce r successes in a negative binomial experiment. The probability distribution of a negative binomial random variable is called a negative binomial distribution, this distribution is known as the Pascal distribution".

And the probability mass function is given by:

P(X=x) = (x+r-1 C k)p^r (1-p)^{x}

Where r represent the number successes after the k failures and p is the probability of a success on any given trial.

Solution to the problem

For this case the likehoof function is given by:

L(\theta , x_i) = \prod_{i=1}^n f(\theta ,x_i)

If we replace the mass function we got:

L(p, x_i) = \prod_{i=1}^n (x_i +r-1 C k) p^r (1-p)^{x_i}

When we take the derivate of the likehood function we got:

l(p,x_i) = \sum_{i=1}^n [log (x_i +r-1 C k) + r log(p) + x_i log(1-p)]

And in order to estimate the likehood estimator for p we need to take the derivate from the last expression and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\frac{x_i}{1-p}

And we can separete the sum and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}

Now we need to find the critical point setting equal to zero this derivate and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}=0

\sum_{i=1}^n \frac{r}{p} =\sum_{i=1}^n \frac{x_i}{1-p}

For the left and right part of the expression we just have this using the properties for a sum and taking in count that p is a fixed value:

\frac{nr}{p}= \frac{\sum_{i=1}^n x_i}{1-p}

Now we need to solve the value of \hat p from the last equation like this:

nr(1-p) = p \sum_{i=1}^n x_i

nr -nrp =p \sum_{i=1}^n x_i

p \sum_{i=1}^n x_i +nrp = nr

p[\sum_{i=1}^n x_i +nr]= nr

And if we solve for \hat p we got:

\hat p = \frac{nr}{\sum_{i=1}^n x_i +nr}

And if we divide numerator and denominator by n we got:

\hat p = \frac{r}{\bar x +r}

Since \bar x = \frac{\sum_{i=1}^n x_i}{n}

4 0
3 years ago
State the domain and range of the following relation.
olga nikolaevna [1]

Answer:

Step-by-step explanation:

domain (ur x values) = -3,-1,1,2

range (ur y values) = -3,1,2,4

do not have to write them more then once

answer is C

5 0
3 years ago
Read 2 more answers
Use the formula you just learned to help you complete the following. A circle’s diameter is approximately 14 cm.
damaskus [11]

Answer:

A= 7

B= 154

Step-by-step explanation:

A: the radius is half of the diameter

B: pie*radius to the second power

3 0
3 years ago
How do you simplify this expression? -12 divided by 3•(-8+(-4)^2-6)+2
stepan [7]

I good accumulator to use would be symbolab.com

The answer would be 3072/5629

5 0
3 years ago
What is the remainder when (3x4 + 2x3 − x2 + 2x − 19) ÷ (x + 2)?<br><br> 0<br> 5<br> 10<br> 15
Elanso [62]

Answer:  Second option is correct.

Explanation:

Since we have given that

f(x)=3x^4+2x^3-x^2+2x-19

And g(x)=x+2

To find the remainder, we use the Remainder Theorem, which states that when f(x) is divided by (x-c) then the f(c) is the required remainder.

So,

Here, we have,

x+2=0\\\\x=-2

So, we will find f(-2) which will give us the required remainder,

f(-2)=3(-2)^4+2(-2)^3-(-2)^2+2(-2)-19\\\\f(-2)=(3\times 16)-(2\times 8)- 4-4-19\\\\f(-2)=48-16-36-4-19\\\\f(-2)=5

Hence, Second option is correct.

7 0
3 years ago
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