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gulaghasi [49]
4 years ago
12

What is the reasonable estimate for -3/2 x -5 1/4

Mathematics
2 answers:
Ahat [919]4 years ago
6 0

Answer:

Step-by-step explanation:

First of all, the estimate will be +, because (-)(-) = (+).

So the problem boils down to approx 1 1/2 times 5, which comes out to 7 1/2.

7 1/2 is a reasonable estimate.

Please, when answer choices are given you, share them.

Lady bird [3.3K]4 years ago
3 0

Answer:

7.875......7.9.....or 8

Step-by-step explanation:

-3÷2×-21÷4= 7.875

63÷8=7.875

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Does the table represent a linear function? Why or why not.
Elza [17]

Answer:

B?

Step-by-step explanation:

4 0
2 years ago
0.05 is 1/10 the value of <br>A. 5 <br>B. 0.005<br>C. 0.5 <br>D. 50<br>​
anastassius [24]

Answer:

C.

Step-by-step explanation:

as 0.05 is 1/10 of a number, multiplying 0.05 by 10 will give you the number that when divided by 10 will give you 0.05. Hence just multiply 0.05 by 10 and you get 0.5.

8 0
3 years ago
Solve the system of equations.<br> 12x - 5y = –20<br> y=x+4<br> 2 =<br> Y=
VARVARA [1.3K]

Answer:

Solution :

{x,y} = {0/14261512,4}

Step-by-step explanation:

Solve by Substitution :

// Solve equation [2] for the variable y

[2] y = x + 4

// Plug this in for variable y in equation [1]

[1] 12x - 5•(x +4) = -20

[1] 7x = 0

// Solve equation [1] for the variable x

[1] 7x = 0

[1] x = 0

// By now we know this much :

x = 0

y = x+4

// Use the x value to solve for y

y = (-0/14261512)+4 = 4

4 0
3 years ago
Read 2 more answers
Have many times does 246 go into 6
eduard
None. If you think about it, 246 is greater than 6, so how can fit 246 into 6? Think about it this way . . how many times can you fit an elephant into a garden hose? . . yeah . . you probably can't . . try reposting your question . . and try making more sense of it next time. :)
8 0
4 years ago
Read 2 more answers
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
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