Answer:
3.8
Step-by-step explanation:
We are going to plug in the values of the equation, so h(t)=-4.9^2+v0t+h0 will
now be h(t)=-4.9^2+0+70
Now we will find the a b and c of the equation, a=-4.9 b=0 c=70
Now we must find the discriminant of the equation, which the equation for that is D=b^2+(-4)(a)(c)
So D=1,372
Now we use the quadratic formula (see picture below for finished product)
Absolute value is alwas positive
so all of them excet the 3rd one are false
|w|=0 has 1 solution
if the last one was |w|=1 then ther would be 2 solutions, -1 and 1
answer is |w|=0
Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
Answer:
x=5/2, y=-3/2. (5/2, -3/2).
Step-by-step explanation:
2=2y+5
3y-3x=-12
--------------
2-5=2y
2y=-3
y=-3/2
3(-3/2)-3x=-12
-9/2-3x=-12
3x=-9/2-(-12)
3x=-9/2+12
3x=-9/2+24/2
3x=15/2
x=(15/2)/3
x=(15/2)(1/3)
x=15/6=5/2
