All categories

4 years ago

What is f(x)=2x^2+3x+7 is x=-5

Mathematics

1 answer:

Mice21 [21]4 years ago

4 0

F(-5) = 2(-5)² + 3(-5) + 7
f(-5) = 2(25) - 15 + 7
f(-5) = 50 - 8
f(-5) = 42

You might be interested in

Find the value of c so that (x+1) is a factor of the polymonial p(x)=5x^4+7x^3-2x^2-3x+c

Andru [333]

Answer:

BRAINLIEST PLZZZZ

Step-by-step explanation:

Also given that (x+1) is factor of given polynomial p(x).

Need to determine value of constant c.

We will be solving above problem using factor theorem.

Factor theorem says that if ( x – a) is a factor of any polynomial f(x) , then f(a) = 0.

As in our case f(x) = p(x) and factor of p(x) is (x + 1) , which can be rewritten as (x – ( -1)) , so "a" in our case is -1 .

According to factor theorem p(-1) = 0

On substituting x = -1 , in given expression of p(x) we get

Hence value of c in the given polynomial is 1

3 0

4 years ago

Read 2 more answers

Un bosque de 2 km2 está formado por hayas y pinos. Las hayas ocupan 380.000 m2 ¿Cuántos metros cuadrados ocupan los pinos?

Ivanshal [37]

Answer:

Los pinos ocupan $\\ 1620000m^{2}$ o 1 millón seiscientos veinte mil metros cuadrados.

Step-by-step explanation:

Una manera de resolver este problema es la siguiente:

$\\ 1km^{2} = 1km * 1km = 1000m * 1000m = 1000000m^{2}$

$\\ 2km^{2} = 2km * 1km = 2000m * 1000m = 2000000m^{2} = 2 * 10^{6}m^{2}$

En palabras, $\\ 2km^{2} = 2000000m^{2}$ , o dos kilómetros cuadrados son iguales a 2 millones de metros cuadrados.

Sabemos que:

Estos $\\ 2km^{2} = 2000000m^{2}$ de bosque lo ocupan hayas y pinos, y, adicionalmente,
Las hayas ocupan $\\ 380000m^{2}$ .

De esta manera, la parte que ocupan los pinos es el total del bosque menos el área ocupada por las hayas. Por lo tanto, el área ocupada por los pinos es:

$\\ 2000000m^{2} - 380000m^{2}$

$\\ 1620000m^{2}$

¿Cuántos metros cuadrados ocupan los pinos?

Los pinos ocupan, entonces, $\\ 1620000m^{2}$ o 1 millón seiscientos veinte mil metros cuadrados.

8 0

3 years ago

Math help please ………….

Vaselesa [24]

Answer:

if the terms are approaching zero then it is convergent.

Therefore the stated series is convergent

Step-by-step explanation:

7 0

3 years ago

The semiannual tuition payment at a major university is expected to be $30,000 for the 4 years beginning 18 years from now. What

elena-14-01-66 [18.8K]

Answer:

$49,216.78

Step-by-step explanation:

A(n,k) = R[1-(1+i)^-n / i) (1+i)^-k

A = Present value of deferred annuity

R = Payment at the end of period

R = 30,000

i = 0.06 / 2

n = (4)*2 = 8

k = deferred period, (18)*(2) = 36

A(n,k) = 30,000*(1-(1+0.04)-^8 / 0.04)*(1+0.04)^-36

A(n,k) = 30,000*(1-(1.04)^-8 / 0.04)*(1.04)^-36

A(n,k) = 30,000*(1 - 0.730690205/0.04) * 0.24366872185

A(n,k) = 30,000*(0.269309795 / 0.04)*0.24366872185

A(n,k) = 30,000*6.732744875*0.24366872185

A(n,k) = 49216.78014700164

A(n,k) = $49,216.78

So the lump sum payment that the university accept now is $49,216.78

6 0

3 years ago

What is the solution to the system of equations graphed below?

Marina CMI [18]

the answer is a. 1,-2

7 0

3 years ago