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nignag [31]
3 years ago
6

What are the solutions for the equation 3(5x-1)^2=27

Mathematics
1 answer:
amm18123 years ago
4 0
See, pls, the suggested explanation:
3(5x-1)²=27 ⇔ 75x²-30x-24=0 ⇔ 25x²-10x-8=0 ⇒
\left[\begin{array}{ccc}x= \frac{5-15}{25} \\x= \frac{5+15}{25} \end{array}\right \ =\ \textgreater \  \   \left[\begin{array}{ccc}x=- \frac{2}{5} \\\ x= \frac{4}{5} \end{array}\right
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Round each number to the place of underlined digit: <br> *1*60,656<br> 1-is underlined
Vinvika [58]

take the number to the right of the underlined digit. if its 4 or less, the digits of the underlined one to the left stay the same, while the digits on the right are turned into 0's.

I'll do a few to help you out:

1. *1*60,656 = 200,000

2. *1*49,590 = 100,000

3. 117,*8*21 = 117,800

7 0
3 years ago
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If g(x) = 1 - ¾ x <br> find: -5g(4) - 1
cricket20 [7]

Answer:

<u>-</u><u>5</u><u>g</u><u>(</u><u>4</u><u>)</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>is</u><u> </u><u>9</u>

Step-by-step explanation:

g(x) = 1 -  \frac{3}{4} x

when x is 4:

g(4) = 1 -  \frac{3}{4}  \times 4 \\  = 1 - 3 \\  =  - 2

therefore:

- 5g(4) - 1 =  - 5( - 2) - 1 \\  = 10 - 1 \\  = 9

5 0
3 years ago
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How do I work this problem?
Vinvika [58]
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Solve. Write your answer in interval notation.<br> 5x+3&lt;−27 or 3x+3≥18
harina [27]

Answer:

(-∞, 6) or [5, ∞)

Step-by-step explanation:

subtract 3

5x< -30 or 3x ≥ 15 .

divide

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3 years ago
A newspaper began publication in 1897 and was printed daily for 76 years . In what year did the newspaper stop publication ?
valentina_108 [34]

Answer:

1973

Step-by-step explanation:

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