How can i solve for x? <br>2x-y=3

What is the measure of

stepan [7]

Answer:

Angle A is 37 degrees, Angle B is 82 degrees, Angle C is 61 degrees

Step-by-step explanation:

Exterior angles are the supplement of interior angles, so subtract 143 from 180 to find Angle A.

180 - 143 = 37

All angles add up to 180.

37 + 61 = 98

180 - 98 = 82

Angle B is 82 degrees.

Hope this helped. :)

7 0

2 years ago

Katie has $6,500 in a saving account if she earns 6% interest every month how much money does Katie have in your bank account af

Dennis_Churaev [7]

Answer:

i believe the answer is 2,340

Step-by-step explanation:

6 0

2 years ago

The graph of a line passes through the points (0,-2) and (6,0). what is the equation of the line?

nirvana33 [79]

Answer:

y = 1/3x - 2

Step-by-step explanation:

We are asked to find the equation of a line with two points

Step1: find the slope

m = (y_2 - y_1)/(x_2 - x_1)

( 0 , -2) (6 , 0)

x_1 = 0

y_1 = -2

x_2 = 6

y_2 = 0

Insert the values

m = ( 0 - (-2)/ (6 - 0)

m = ( 0 + 2)/(6 - 0)

m = 2/6

m = (2/2)/(6/2)

m = 1/3

Step 2 : substitute m into the equation of line

y = mx + c

y = intercept y

m = slope

x = intercept x

c = intercept

y = 1/3x + c

Step 3: sub any of the two points

Let's pick ( 6 ,0)

x = 6

y = 0

Insert the values into

y = 1/3x + c

0 = 1/3(6) + c

0 = 1*6/3 + c

0 = 6/3 + c

0 = 2 + c

c = 0 - 2

c = -2

Sub c = -2

y = 1/3x - 2

The equation of the line is

y = 1/3x - 2

5 0

3 years ago

Plzz help asap.......

SSSSS [86.1K]

Answer:

29.78 feet

Step-by-step explanation:

4 0

3 years ago

All vectors are in Rn. Check the true statements below:

Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

$Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y$

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that $||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}$ . Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then $||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||$ .

C) Consider $S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2$ . This set is orthogonal because $(0,2)\cdot(2,0)=0(2)+2(0)=0$ , but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in $\mathbb{R}^n$ . Then the columns of A form an orthonormal set. We have that $A^{-1}=A^t$ . To see this, note than the component $b_{ij}$ of the product $A^t A$ is the dot product of the i-th row of $A^t$ and the jth row of $A$ . But the i-th row of $A^t$ is equal to the i-th column of $A$ . If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then $A^t A=I$

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set $\{u_1,u_2\cdots u_p\}$ and suppose that there are coefficients a_i such that $a_1u_1+a_2u_2\cdots a_nu_n=0$ . For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then $a_i||u_i||=0$ then $a_i=0$ .

5 0

3 years ago

How can i solve for x? 2x-y=3