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goblinko [34]
3 years ago
14

Which complex number is the simplified form of 2+5i3+i2+5i3+i?

Mathematics
1 answer:
viva [34]3 years ago
8 0

Answer:

Option (1)

Step-by-step explanation:

The given complex  number is (2+5i)/(3+i)

multiplying the numerator and the denominator by the conjugate of (3+i) which is (3-i)

The denominator = (3+i)(3-i) = 3² - i² = 9 - (-1) = 10

The numerator  = (2 + 5 i ) ( 3 - i ) = 2(3-i) + 5i (3 - i)

                          = 6 - 2i + 15 i - 5 i²

                          = 6 + 13 i + 5 = 11 + 13 i

So, the given complex number can be simplified to ( 11 + 13i)/10

Distributing numerator over denominator.

The simplified  number = (11/10) + (13/10) i

The answer is option (1)

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Find the missing lengths: LK=15 and KH=9, find KI and HI.
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Answer:

KI=11.25 and HI=6.75

Step-by-step explanation:

Consider the below figure attached with this question.

According to Pythagoras Theorem:

base^2+perpendicular^2=hypotenuse^2

Use Pythagoras in triangle HKL

LH^2+KH^2=LK^2

(LH)^2+9^2=15^2

(LH)^2+81=225

(LH)^2=144

Taking square root on both sides.

LH=12

Let length of HI be x.

LI = 12+x

Use Pythagoras theorem in ΔKLI,

(KI)^2+15^2=(12+x)^2

(KI)^2+225=x^2+24x+144

(KI)^2=x^2+24x+144-225

(KI)^2=x^2+24x-81...(1)

Use Pythagoras theorem in ΔHKI,

(KI)^2=x^2+9^2

(KI)^2=x^2+81...(2)

From (1) and (2) we get

x^2+81=x^2+24x-81

24x=162

x=\dfrac{162}{24}=6.75

Hence, the measure of HI is 6.75 units.

Substitute x=6.75 in equation (2).

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Taking square root on both sides.

KI=\sqrt{126.5625}

KI=11.25

Hence, the measure of KI is 11.25 units.

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3 years ago
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