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goblinko [34]
3 years ago
14

Which complex number is the simplified form of 2+5i3+i2+5i3+i?

Mathematics
1 answer:
viva [34]3 years ago
8 0

Answer:

Option (1)

Step-by-step explanation:

The given complex  number is (2+5i)/(3+i)

multiplying the numerator and the denominator by the conjugate of (3+i) which is (3-i)

The denominator = (3+i)(3-i) = 3² - i² = 9 - (-1) = 10

The numerator  = (2 + 5 i ) ( 3 - i ) = 2(3-i) + 5i (3 - i)

                          = 6 - 2i + 15 i - 5 i²

                          = 6 + 13 i + 5 = 11 + 13 i

So, the given complex number can be simplified to ( 11 + 13i)/10

Distributing numerator over denominator.

The simplified  number = (11/10) + (13/10) i

The answer is option (1)

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What is an algebraic expression for, the sum of s and t ?​
denis-greek [22]

Answer:

\Huge \boxed{s+t}

Step-by-step explanation:

The sum is the result obtained from adding two or more values together.

The sum of <em>s</em> and <em>t</em> is the result obtained from adding <em>s</em> and <em>t</em> together.

<em>s </em>+<em> t</em>

4 0
3 years ago
Help pls!<br> simplify<br> -6 x^{2} ÷ 12 - 2(-7)<br><br> a. -17<br> b. 35<br> c. -35<br> d. 11
Mariana [72]

Answer:

11

Step-by-step explanation:

Given: \frac{-6^{2}}{12} -2(-7)

Using PEDMAS rule to solve it.

Now, simplifying:

We first open parenthesis which is (-7) = -7

= \frac{-6^2}{12}-2\times -7

Now, we evaluate the exponent which is -6^2=-36

Next, we divide -36 by 12 to get -3

= \frac{-36}{12}-2\times -7 \\= -3 -2\times -7

Next, we multiply -2 and -7 to get 14

= -3 + 14

Lastly, we add -3 and 14 to get 11

= 11

∴ Answer is 11

5 0
3 years ago
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irinina [24]

Answer:

7.2

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6.4

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3 0
3 years ago
Read 2 more answers
Please Help me with the last three questions!<br> It is urgent!
MrMuchimi
Answers:
1. X= 0
2. X= 0
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You can use this method to solve them step by step, hope it will help!

8 0
3 years ago
Of the following approximate conversions of Fahrenheit into Celsius, which is most accurate?
asambeis [7]

Answer:

its B

Step-by-step explanation:

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