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Misha Larkins [42]
3 years ago
9

Find the exact value of sine [2 cosine Superscript negative 1 Baseline (- StartFraction StartRoot 2 EndRoot/2 EndFraction )] = n

othing
Mathematics
1 answer:
Nady [450]3 years ago
3 0

Answer:

\frac{3\pi}{2}.

Step-by-step explanation:

The given expression is

2\cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)

It can be rewritten as

2\cos^{-1}\left(-\frac{1}{\sqrt{2}}\right)

2\left [\pi-\cos^{-1}\left(\frac{1}{\sqrt{2}}\right)\right]            [\because \cos^{-1}(-x)=\pi-\cos^{-1}(x), x\in [-1,1]]

2\left [\pi-\cos^{-1}\left(\cos \frac{\pi}{4}\right)\right]

2\left [\pi-\frac{\pi}{4}\right]

2\left [\frac{4\pi-\pi}{4}\right]

\frac{3\pi}{2}

Hence, the exact value of given expression is \frac{3\pi}{2}.

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