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Westkost [7]
3 years ago
8

The circle graph shows how Tremaine divided his time on the computer last week Tremaine's Computer Time Games 25% Homework 20% R

esearch 5% Other 10% Social media 40% Tremaine used the computer a total of 30 hours last week. How many more hours did Tremaine use the computer to play video games than to do research? 6 hours 20 hours 75 hours • 15 hours
Explain the answer choice you choose. I will mark you brainlist!​

Mathematics
1 answer:
wel3 years ago
6 0

Step-by-step explanation:

25%×24 =6 jahdyheuxlfoodnxhydushgdys

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The graph of a linear equation contains the points (3,11) and (-2,11). Which point also lies on the graph?(YOU MUST SHOW WORK)
dexar [7]
Y= ax+b

when x=3, y=11   and when x= -2, y=11
          3a+b=11
          -2a+b=11    | * -1
3a+b=11
2a-b=-11
------------
  5a=0, a=0:5, a=0
⇒ b=11
y=11 for every x
So ( 1,11)  or (2,11) are also points on the graph
3 0
3 years ago
Solve the inequality 5(2x + 1) &lt; 10.<br> х&lt; 1/2<br> x&gt; 1/2<br> х&lt; 3/2<br> x&gt; 3/2
Maurinko [17]

Answer:

x < 1/2

Step-by-step explanation:

5(2x + 1) < 10

Divide each side by 5

5/5(2x + 1) < 10/5

2x+1 < 2

Subtract 1 from each side

2x+1-1 < 2-1

2x <1

Divide each side by 2

2x/2 <1/2

x < 1/2

4 0
3 years ago
Read 2 more answers
Simply the equation 3m + ( m + 5 )
Elena L [17]

Answer:

4m+5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The value of a machine depreciates each year by 5% of its value at the beginning of that year.If its value when new on 1st Janua
luda_lava [24]

Answer:

6460 pounds approx.

Step-by-step explanation:

Depreciation = P( 1 - r/100)^n [ n = time period, P= Principal and r= rate}

= 10,250(1-5/100)^9

= Approx. 6460 pounds

7 0
3 years ago
part of the river she observed fell 1.68 millimeters per year for 1.5 years. Use the distributive property to calculate the exac
Alecsey [184]
1.68 mm per year for 1.5 years could be rewritten as 
(2.00-0.32) mm per year for 1.5 yrs.

Multiply:  (1.5 yrs)(2.00-0.32)(mm/yr) = 3 mm + 0.48 mm = 3.48 mm

This approach makes use of the distributive property of multiplication.
8 0
3 years ago
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