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Mamont248 [21]
3 years ago
9

A group of 72 children completed a survey on what kind of sport they like. The choices were: Chess, Swimming, and Football. Ever

yone liked at least one sport except 7 kids, which doesn't like any of these three kind of sports.
12 children liked Chess and Football but not Swimming,

16 children liked Chess and Swimming but not Football,

8 children liked Swimming and Football but not Chess,

10 children liked Chess only,

40 children liked Swimming,

32 student liked Football.


What is the probability that a randomly-chosen child from this group likes either Chess or Swimming but not Football?
Mathematics
1 answer:
Svetach [21]3 years ago
3 0

Answer:

19/72

Step-by-step explanation:

To calculate the probability that a randomly-chosen child from this group likes either Chess or Swimming but not Football?

We already know the number that liked chess only which is 10, we have to solve for those that liked swimming only which is

8+7+16+x = 40

x which represent swimming only is

40-31 = 9

Thus probability = 10/72 + 9/72 = 19/72

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Answer:

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Step-by-step explanation:

Step 1: Add -x to both sides.

x−5y+−x=−18+−x

−5y=−x−18

Step 2: Divide both sides by -5.

−5y−5=−x−18−5

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Answer:

Los lados del triángulo rectángulo miden 3, 4 y 5, respectivamente.

Step-by-step explanation:

Un triángulo rectángulo puede ser descrito mediante el teorema de Pitágoras, para el caso de tres lados representando tres números enteros consecutivos, tenemos que:

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Donde n es un número natural.

A continuación, expandimos la expresión y resolvemos:

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