1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Kobotan [32]
3 years ago
9

Solve for x. Round to the nearest tenth.

Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

x = 9.6

Step-by-step explanation:

You might be interested in
the perimeter of a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width of the rectangle, in feet
zubka84 [21]

Answer:

The width of the rectangle is <u>7 feet</u>.

Step-by-step explanation:

Given:

The perimeter of a rectangle is 54 feet, and the length is 13 feet more than the width.

Now, to find the width of the rectangle.

Let the width be x.

So, the length is 13+x.

Perimeter = 54 feet.

Now, to get the width we put formula:

Perimeter=2(length+width)

54=2(13+x+(x))\\54=2(13+x+x)

54=2(13+2x)

54=26+4x

<em>Subtracting both sides by 26 we get:</em>

28=4x

<em>Dividing both sides by 4 we get:</em>

7=x\\x=7\ feet.

Therefore, the width of the rectangle is 7 feet.

4 0
3 years ago
Please help me answer this ASAP! The two-way table shows the number of ninth and tenth graders who prefer going to sporting even
Elis [28]
<h2>Answer</h2>

0.43

<h2>Explanation</h2>

Remember that RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so Frecuency=6. Now, the sum of all frequencies will be the sum of all the 10th graders, so SumOfAllFrecuencies=6+8=14. Let's replace the values:

RelativeFrecuency=\frac{Frecuency}{SumOfAllFrecuencies}

RelativeFrecuency=\frac{6}{14}

RelativeFrecuency=0.4285

And rounded to the nearest hundredth:

RelativeFrecuency=0.43

4 0
3 years ago
Median for 15,17,15,16,14,18,5
Andrei [34K]

Answer:

the median is 15

Explanation:

you can find the median by arranging the numbers from smallest to largest and finding the number in the middle.

5 14 15 <u>15</u> 16 17 18

in this case, the number in the middle is 15 so the median for this data set is 15.

i hope this helps! :D

4 0
2 years ago
I need some help please
muminat
Answer: 113.0 ft (bottom right corner)

=====================================

Explanation:

The triangle has a horizontal leg of 220 ft and a vertical leg of x ft. We'll use the tangent rule to connect the opposite side and adjacent side

opposite side = x
adjacent side = 220
this is with the reference angle shown in the diagram

So,
tan(angle) = opposite/adjacent
tan(26) = x/220
220*tan(26) = x
x = 220*tan(26)
x = 107.301169 ... see note below
x = 107.3

Now that we know the approximate value of x, we add on 5.7 to get
x+5.7 = 107.3+5.7 = 113.0

note: make sure your calculator is in degree mode. The value is approximate to 6 decimal places

3 0
3 years ago
If allie has five melons and jess take two away how many melons does josh have?​
sashaice [31]
Josh had zero melons because he never got any .
7 0
3 years ago
Other questions:
  • What is the volume of the tissue paper in the packaging box?
    6·1 answer
  • If i have a 78 for the year what can I make on my exam to pass
    7·1 answer
  • Round 440.221281415 to 2 decimal places
    5·1 answer
  • Does anyone know this?
    9·1 answer
  • I’m confused on this one
    6·1 answer
  • Use the distributive property to simplify 5(2x+3). <br><br> i will give you 10 points
    5·1 answer
  • How do I make 120% into a fraction and a decimal number?
    12·2 answers
  • Which mixed number is equivalent to 606/100
    11·1 answer
  • Solve y3 = 64.
    7·1 answer
  • Richard and Teo have a combined age of 35. Richard is 14years older than twice​ Teo's age. How old are Richard and​ Teo?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!