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3 years ago

Aliyah $24 to spend on seven pencils. After buying them she had $10. How much did each pencil cost?

2 answers:

5 0

Each pencil cost $2.

Explanation: She had $24 before buying the pencils and after she had $10. 24-10=14 so the total she spent on pencils was $14. She bought 7 pencils so you divide 14 by 7 (14/7=2) which equals 2. So each pencil cost $2.

evablogger [386]3 years ago

5 0

Answer:

They are $2 dollars a piece

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Write the fraction 7/10 as a sum of fraction three different ways

LUCKY_DIMON [66]

A . 2/10 + 5/10= 7/10
B. 3/10 + 4/10= 7/10
C. 6/10 + 1/10 =7/10

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3 years ago

Which of the following would not represent the phrase “the difference of two numbers divided by 5”?

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It would be (a) because it is now
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2 years ago

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Ivenika [448]

Answer:

Step-by-step explanation:

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2 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

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2 years ago

Please help me out with this!!!!!!!

Bad White [126]

Answer:

Step-by-step explanation:

The line on the right has equation y = x + 1

The absolute value function always gives a positive value

Thus the equation is y = | x + 1 | → A

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2 years ago