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DIA [1.3K]
3 years ago
14

Write an exponential function in the form y = ab* that goes through points (0,12) and (2,768).

Mathematics
1 answer:
adell [148]3 years ago
3 0

The exponential function is y=12(8)^{x}

Step-by-step explanation:

The form of the exponential function is y=ab^{x} , where

  • a is the value of y when x = 0
  • b is the rate of change

∵ The form of the exponential function is y=ab^{x}

∵ The function goes through points (0 , 12) and (2 , 768)

- Substitute the coordinates of the first point to find the value of a

∵ x = 0 and y = 12

∴ 12=ab^{0}

∵ b^{0}=1

∴ 12 = a(1)

∴ a = 12

Substitute the value of a in the form of the function

∴ y=12(b)^{x}

- Substitute the coordinates of the second point to find the value of b

∵ x = 2 and y = 768

∴ 768=12(b)^{2}

- Divide both sides by 12

∴ 64 = b²

- Take √ for both sides

∴ b = 8

- Substitute the value of b in the form of the function

∴ y=12(8)^{x}

The exponential function is y=12(8)^{x}

Learn more:

You can learn more about the logarithmic function in brainly.com/question/1447265

#LearnwithBrainly

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Urgent. There are 12 coloured counters in a bag. The counters are black, white or grey A counter is chosen at random. The probab
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Answer:

1/12

Step-by-step explanation:

<u>Needed information</u>

\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}

The sum of the probabilities of all outcomes must equal 1

<u>Solution</u>

We are told that the probability that the counter is <em>not</em> black is 3/4.  

As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>black by subtracting 3/4 from 1:

\sf P(counter\:not\:black)=\dfrac34

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We are told that the probability that the counter is <em>not </em>white is 2/3.  

As the sum of the probabilities of all outcomes <u>must equal 1</u>, we can work out the probability that the counter <em>is </em>white by subtracting 2/3 from 1:

\sf P(counter\:not\:white)=\dfrac23

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We are told that there are black, white and grey counters in the bag.  We also know that the sum of the probabilities of all outcomes must equal 1.  Therefore, we can work out the probability the counter is grey by subtracting the probability the counter is black and the probability the counter is white from 1:

\begin{aligned}\sf P(counter\:grey) & = \sf1-P(counter\:black)-P(counter\:white)\\\\ & =\sf 1-\dfrac14-\dfrac13\\\\ & = \sf \dfrac{12}{12}-\dfrac{3}{12}-\dfrac{4}{12}\\\\ & = \sf \dfrac{12-3-4}{12}\\\\ & = \sf \dfrac{5}{12}\end{aligned}

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