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Mnenie [13.5K]
3 years ago
13

Asif makes a cuboid of plasticine of sides 75cm, 35cm and 21cm. How many such cuboids will he need to form a cube?

Mathematics
1 answer:
algol [13]3 years ago
8 0

Answer:

The number of cuboids that will be needed to form a cube is 2625 cuboids

Step-by-step explanation:

To form a cube, we have;

The length = The height = The depth

The dimensions of the given cuboid = Length = 75 cm, the width = 35 cm, the depth = 21 cm.

Therefore;

The lowest common multiple of 75, 35, and 21, for the cuboid is given as follows;

75 = 5 × 5 × 3

35 = 5 × 7

21 = 3 × 7

Therefore, multiplying 75 by 7, we get;

75 × 7 = 525

Since 7, 5 and 3 are factors of 525, 35 and 21, can also be factors as we check;

525/35 = 15

525/21 = 25

Therefore, the cube will be;

The length of the cube will consist of 7 pieces of the cuboid, arranged with the side 75 cm facing the front

The depth of the cuboid will be 15 cuboids with the side 35 cm facing the sides

The height of the cuboid will be 25 cuboids with the side 21 cm high

The total number of cuboids is therefore;

7 × 15 × 25 = 2625 cuboids

The number of cuboids that will be needed to form a cube = 2625 cuboids.

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9514 1404 393

Answer:

  • width: 4 ft
  • length: 13 ft

Step-by-step explanation:

Let w represent the width of the rectangle. Then the length is 3w+1 and the area is ...

  w(3w+1) = 52

  3w²  +w -52 = 0

To factor this equation, we need factors of 3·52 = 156 that have a difference of 1. These values are 12 and 13, so we can rewrite the equation as ...

  3w² +13w -12w -52 = 0

  w(3w +13) -4(3w +13) = 0

  (w -4)(3w +13) = 0

The positive value of w that makes a factor zero is ...

  w = 4

Then the length is 3w+1 = 3(4) +1 = 13.

The length is 13 ft; the width is 4 ft.

8 0
3 years ago
What angle is this?<br><br> -Complementary <br> -Supplementary<br> -Vertical<br> -Adjacent
GuDViN [60]

Answer:

Adjacent

Step-by-step explanation:

Since angle a and b are right next to each other, they would be adjacent.

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3 years ago
Ronald Sutter, an assembly line worker, earns $16.655 per hour. He typically works 36.225 hours per week. What is his usual stra
Nadusha1986 [10]

His usual straight-time pay is $603.327375 per week

<h3>How to determine his usual straight-time pay?</h3>

The given parameters are

Rate = $16.655 per hour

Duration = 36.225 hours per week

His usual straight-time pay is calculated as

Usual pay = Rate * Duration

So, we have

Usual pay = $16.655 per hour * 36.225 hours per week

Evaluate the product

Usual pay = $603.327375 per week

Hence, his usual straight-time pay is $603.327375 per week

Read more about linear rates at

brainly.com/question/7040405

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2 years ago
Write an equation representing how much Keith paid.
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3 years ago
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Write as a square of a binomial: 4.8xy+36y^2+0.16 i will give brainliest plz solve
Sonja [21]

Answer:

(0.4x + 6y)^2

Step-by-step explanation:

Given

4.8xy+36y^2+0.16x^2

Required

Express as a binomial squared

4.8xy+36y^2+0.16x^2

Rewrite as:

0.16x^2+4.8xy+36y^2

Expand

0.16x^2 + 2.4xy + 2.4xy + 36y^2

Factorize:

0.4x(0.4x + 6y) + 6y(0.4x + 6y)

Factor out 0.4x + 6y

(0.4x + 6y)(0.4x + 6y)

Express as a square:

(0.4x + 6y)^2

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3 years ago
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