Mean, m = 18 in
Standard deviation, SD = 2.2 in
Range: 16 ≤ X ≤ 21 in
Calculating Z value,
Z = (X-m)/SD
Then,
Z1 = (16-18)/2.2 ≈ -0.91
Z2 = (21-18)/2.2 ≈ 1.36
From Z table, and at Z1 = -0.91, and Z2 = 1.36;
P(16) = 0.1814
P(21) = 0.9131
Therefore,
P(16≤X≤21) = 0.9131 - 0.1814 = 0.7317
The probability that a child selected randomly measures between 16 and 21 in is 0.7317.
Im not sure but I think u have to add or multiply
Answer:
The worded number equation translates to 4=6/100
4/1 = 3/50
(Now you need to cross multiply)
200/3
66.66 = answer
Answer:
30 pounds
Step-by-step explanation:
create a proportion and cross-multiply to solve
let x = $45 worth of tomatoes, in pounds
21 / 31.5 = x / 45
31.5x = 945
x = 30
1/4 of $160 is $40. 3/10 of $120 is $36.
5/21 of 84 is $20.16. This leaves him with $63.84.
