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marissa [1.9K]
3 years ago
8

Please solve I’m confused

Mathematics
2 answers:
leva [86]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Applying the rule of exponents

(a^m)^{n} = a^{mn}

note that

a^{m} × a^{n} = a^{(m+n)}

Hence

(2^3)^{1} = 2^{3(1)} = 2^{3} = 8

The classmate has mistakenly added the exponents to obtain

(2^3)^{1} = 2^{(3+1)} = 2^{4} = 16 ← incorrect

snow_lady [41]3 years ago
4 0

Answer:

A. the proper steps that should have been taking would be to first would be to raise 2 to the power of 3, which would give you 8. Then raise it to the power of 1. So the most likely error is C. they added the exponents.

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I think it's A and C

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Answer:

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Step-by-step explanation:

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SAT scores are normed so that, in any year, the mean of the verbal or math test should be 500 and the standard deviation 100. as
vovangra [49]

Answer:

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P(-1

P(-1

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the SAT scores of a population, and for this case we know the distribution for X is given by:

X \sim N(500,100)  

Where \mu=500 and \sigma=100

We are interested on this probability

P(X>625)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>625)=P(\frac{X-\mu}{\sigma}>\frac{625-\mu}{\sigma})=P(Z>\frac{625-500}{100})=P(Z>1.25)

And we can find this probability using the complement rule and with the normal standard table or excel:

P(Z>1.25)=1-P(Z

Part b

We are interested on this probability

P(400

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(400

And we can find this probability with this difference:

P(-1

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1

Part c

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.8   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

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If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.842

And if we solve for a we got

a=500 -0.842*100=415.8

So the value of height that separates the bottom 20% of data from the top 80% is 415.8.  

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Answer: $384
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