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-Dominant- [34]
4 years ago
15

If x ml pure alcohol is added to 400 ml of a 15% solution and after adding its strength becomes 32%, then the value of x is

Mathematics
1 answer:
-BARSIC- [3]4 years ago
6 0
We calculate as  follows:

15 mL pure ethanol / 100 mL solution (400 mL) = 60 mL pure ethanol

32% = 32 mL pure ethanol/100 mL solution = 60 mL pure ethanol + x mL pure ethanol / (400 + x)

x = 100 mL pure ethanol was added to the solution ------> OPTION D
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