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Anika [276]
3 years ago
12

a coin lands on heads 200 times. the relative frequency of heads is 0.4. how many times was the coin thrown?

Mathematics
2 answers:
Kazeer [188]3 years ago
7 0

Answer:

The number of times coin thrown was <u>500</u>.

Step-by-step explanation:

Given:

A coin lands on heads 200 times. the relative frequency of heads is 0.4.

Now, to find the times coin was thrown.

Let the number of times coin thrown was be x.

Relative frequency = 0.4.

Number of lands on heads = 200.

So, to get the number of times coin was thrown we put formula:

Relative\ frequency=\frac{Number\ of\ lands\ on\ heads}{Number\ of\ times\ coin\ thrown}

0.4=\frac{200}{x}

<em>By cross multiplying we get:</em>

0.4x=200

<em>Dividing both sides by 0.4 we get:</em>

x=500.

Therefore, the number of times coin thrown was 500.

Vlad [161]3 years ago
7 0

Answer:

500

Step-by-step explanation:

200÷0.4=500

Therefore, the coin was thrown 500 times.

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A chess club with 55 members is electing a new president. Lucy received 33 votes. What percentage of the club members voted for
bonufazy [111]
You would put it up into proportions so 33 over 55 equals x over 100. Then you would cross multiply so 55x=3300. Then you would divide 3300 by 55 and get 60%.
4 0
3 years ago
Red bricks and grey bricks were used to build a decorative wall. The number of red bricks divided by number of grey bricks was 5
azamat
Red bricks : Grey bricks
        5        :            2

Total parts = 5 + 2 = 7

7 parts = 224
-----------------------
Find 1 part:
-----------------------
1 part = 234 ÷ 7
1 part = 32

-----------------------
Find 5 parts:
-----------------------
5 parts = 32 x 5 
5 parts = 160

----------------------------------------------
Answer: 160 Red bricks
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5 0
3 years ago
Please Help! Multiple Choice!
Katyanochek1 [597]

Using the z-distribution, the p-value would be given as follows:

b) 0.0086.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis we test if the means are equal, hence:

H_0: \mu_D - \mu_C = 0

At the alternative hypothesis, it is tested if they are different, hence:

H_1: \mu_D - \mu_C \neq 0

<h3>What are the mean and the standard error for the distribution of differences?</h3>

For each sample, they are given as follows:

  • \mu_D = 12, s_D = \frac{5.2}{\sqrt{73}} = 0.6086
  • \mu_C = 14, s_C = \frac{4.1}{\sqrt{81}} = 0.4556

Hence, for the distribution of differences, they are given by:

  • \overline{x} = 12 - 14 = -2.
  • s = \sqrt{0.6086^2 + 0.4556^2} = 0.76

<h3>What is the test statistic?</h3>

The test statistic is given by:

z = \frac{\overline{x} - \mu}{s}

In which \mu = 0 is the value tested at the null hypothesis.

Hence:

z = \frac{\overline{x} - \mu}{s}

z = \frac{-2 - 0}{0.76}

z = -2.63.

Using a z-distribution calculator, for a two-tailed test, with z = -2.63, the p-value is of 0.0086.

Hence option B is correct.

More can be learned about the z-distribution at brainly.com/question/13873630

#SPJ1

4 0
2 years ago
The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between (height) and (arm span) is shown
sergeinik [125]

Answer: Mike's arm span is 7.165 cm longer than the George's one.

Step-by-step explanation:

We have that the association between height and arm span is modeled by the equation

y = 4.5 + 0.977*x

where y is height and x is arm span.

Mike is 172 cm tall, so his arm span is:

172cm = 4.5 + 0.977*x

x = (172 - 4.5)/0.977 = 171.443 cm

and George is 165 cm tall, so his arm span is:

x = (165 - 4.5)/0.977 = 164.278 cm

Then the difference between their arm span is:

171.443cm - 164.278cm = 7.165 cm

So Mike's arm span is 7.165 cm longer than the George's one.

6 0
3 years ago
Jose earned 29.75 in 3.5 hours how much did he earn in one hour
baherus [9]

Answer:

$8.50

Step-by-step explanation:

$29.75 / 3.5 hours = $8.50 per hour

6 0
3 years ago
Read 2 more answers
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