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miv72 [106K]
3 years ago
9

What are three equivalent ratios the fourth third

Mathematics
1 answer:
Ghella [55]3 years ago
6 0
Three equivalent ratios are: 8/6, 12/9, 16/12
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A has coordinates (1,1) and B has coordinates (4,3). if AB is a side of a square, what is the area of the square?
kvasek [131]
Area of the square:
A = s²
and s = AB = sqrt ( ( 4 - 1 )² + ( 3 - 1 )² )
s = √ ( 9 + 4 ) = √ 13
A = ( √13 )² = 13
Answer: Area of the square is 13 units².
8 0
3 years ago
What is the value of x in the equation 3 = 2x? A. 2/3
Alexxandr [17]
3 divided by 2 is 1.5 so c
6 0
2 years ago
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What is the solution to: <br> T/t-4=t+4/6
S_A_V [24]
\frac{t}{t-4}= \frac{t+4}{6} \\ t \neq 4 \\ 6t=  (t+4)(t-4) \\ 6t=t^2-16 \\ t^2-6t-16=0 \\ D=b^2-4ac=(-6)^2-4*1*(-16)=36+64=100 \\ t_{1,2}= \frac{-bб \sqrt{D} }{2a}  \\ t_1= \frac{6-10}{2}=-2 \\  \ t_2= \frac{6+10}{2}=8

Answer: t=-2, t=8
4 0
3 years ago
Hi are you able to solve it by using a step called exponential equations?
andriy [413]

Given the equation:

6^{2-3x}=6^{-2x-2}

since both bases are 6, we can equate both exponents to get the following equation:

2-3x=-2x-2

solving for x, we get:

\begin{gathered} 2-3x=-2x-2 \\ \Rightarrow-3x+2x=-2-2=-4 \\ \Rightarrow-x=-4 \\ \Rightarrow x=4 \end{gathered}

therefore, the solution of the equation is x = 4

6 0
1 year ago
The national vaccine information center estimates that 90% of americans have had chickenpox by the time they reach adulthood.50
timama [110]
Given:
 p = 90% = 0.9, the probability that an adult has had chickenpox by age 50.
Therefore,
q = 1 - p = 0.1, the probability that an adult has not had chickenpox by age 50.

Part (a)
Because there are only two answers: "Yes" or "No" to whether an adult has had chickenpox by age 50, the use of the binomial distribution is justified.

Part (b):
Calculate the probability that exactly 97 out of 100 sampled adults have had chickenpox.
The probability is
P₁ = ₁₀₀C₉₇ (0.9)⁹⁷ (0.1)³ = 0.0059

Answer: 0.006 or 0.6%

Part (c)
Calculate the probability that exactly 3 adults have not had chickenpox.
Theis probability is equal to 
P₂ = 1 - P₁ = 1 - 0.006 = 0.994

Answer: 0.994 or 99.4%

Part (d)
Calculate the probability that at least 1 out of 10 randomly selected adults have had chickenpox.
The probability is
P₃ = ₁₀C₀ (0.9)⁰ (0.1)¹⁰ + ₁₀C₁ (0.9)¹ (0.1)⁹ = 10⁻¹⁰ + 10⁻⁹ = 10⁻⁹ ≈ 0

Answer: 0

Part (e)
Calculate the probability that at most 3 out of 10 randomly selected adults have not had chickenpox.
The probability is
P₄ = 1 - [₁₀C₀ (0.9)⁰(0.1)¹⁰ + ₁₀C₁ (0.9)¹(0.1)⁹ + ₁₀C₂ (0.9)²(0.1)⁸ + ₁₀C₃ (0.9)³(0.1)⁷]
     = 1 - (10⁻¹⁰ + 9 x 10⁻⁹ + 3.645 x 10⁻⁷ + 8.748 x 10⁻⁶)
     = 1

Answer:  1.0 or 100%

5 0
3 years ago
Read 2 more answers
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