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ehidna [41]
3 years ago
10

Solve: |x-6|=8 A. x=14 and x= -14 B. x= -14 and x=2 C. x=14 and x= -2 D. x= -14 and x= -2

Mathematics
1 answer:
Shalnov [3]3 years ago
7 0

Answer:

x=-2

Step-by-step explanation:

Everything that comes out of absolute value pairs are always positive.

-2-6=-8 but since it is in the absolute value pair, it becomes positive.

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What is the answer -.6x+ .9= 1x+2.4
Mariulka [41]

Answer:

X=-0.9375 or -15/16

Step-by-step explanation:

-0.6+0.9=x+2.4

-0.6x-x=2.4-0.9

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x= -0.9375

4 0
3 years ago
For the functions f(x)=−7x^2−x and g(x)=9x^2−4x, find (f−g)(x) and (f−g)(1)
musickatia [10]

Answer:

See below.

Step-by-step explanation:

f(x)=-7x^2-x\\g(x)=9x^2-4x\\(f-g)(x)=f(x)-g(x)\\(f-g)(x)=(-7x^2-x)-(9x^2-4x)\\(f-g)(x)=-7x^2-x-9x^2+4x\\(f-g)(x)=-16x^2+3x\\\\(f-g)(1)=-16(1)^2+3(1)\\(f-g)(1)=-16+3=-13

5 0
4 years ago
cos theta = 4/5, 0˚< theta < 90˚ use the information given to find sin2theta, cos2theta, and tan 2theta
NikAS [45]
First calculate \sin\theta.

\sin^2\theta+\cos^2\theta=1\\\\\sin^2\theta=1-\cos^2\theta\\\\\sin^2\theta=1-\left(\dfrac{4}{5}\right)^2\\\\\\\sin^2\theta=1-\dfrac{16}{25}\\\\\\\sin^2\theta=\dfrac{9}{25}\quad|\sqrt{(\dots)}\\\\\\\sin\theta=\sqrt{\dfrac{9}{25}}\\\\\\\boxed{\sin\theta=\dfrac{3}{5}}

We take positive value of sinθ because 0° < θ < 90°
Now we could calculate sin2θ, cos2θ and tan2θ:

\sin2\theta=2\sin\theta\cos\theta=2\cdot\dfrac{3}{5}\cdot\dfrac{4}{5}=\dfrac{2\cdot3\cdot4}{5\cdot5}=\dfrac{24}{25}\\\\\\\cos2\theta=\cos^2\theta-\sin^2\theta=\left(\dfrac{4}{5}\right)^2-\left(\dfrac{3}{5}\right)^2=\dfrac{16}{25}-\dfrac{9}{25}=\dfrac{7}{25}\\\\\\&#10;\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=\dfrac{\frac{24}{25}}{\frac{7}{25}}=\dfrac{24\cdot25}{7\cdot25}=\dfrac{24}{7}=3\dfrac{3}{7}
5 0
3 years ago
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siniylev [52]
That is also equal to (9÷1)÷3, so it will be the same as 9÷3. Therefore, the answer is 3.
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Answer: 3 3/4

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