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AleksandrR [38]
2 years ago
6

What is the measure of angle JHN.

Mathematics
2 answers:
Julli [10]2 years ago
5 0

Answer:

it's a)25

Step-by-step explanation:

angle MHL and JHN+NHK should be the same, they both are 95 degrees

gizmo_the_mogwai [7]2 years ago
5 0

Answer:

45°

Step-by-step explanation:

first of all find X

(3x+20) - (x+25) =x + 20

3x+20-x-25=x+20

3x-x+20-25=x+20

2x-5=x+20

collect like terms

2x-x=20+5

x=25°

recall JHN= (x+20)°

x=25

JHN=((25)+20)°

JHN=(25+20)°

JHN=45°

Hope it is helpful

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The ideal (daytime) noise-level for hospitals is 45 decibels with a standard deviation of 10 db; which is to say, this may not b
WINSTONCH [101]

Answer:

<em>(a) A 99% confidence interval for the actual mean noise level in hospitals is </em><em>(44.02 db, 49.98 db)</em><em>. </em>

<em>(b) We can be 90% confident that the actual mean noise level in hospitals is </em><em>47 db</em><em> with a margin of error of </em><em>1.89 db</em><em>. </em>

<em>(c) Unless our sample (of 81 hospitals) is among the most unusual 2% of samples, the actual mean noise level in hospitals is between </em><em>44.41 db and 49.59 db</em><em>. </em>

<em />

Step-by-step explanation:

<em>The problem is incomplete. The questions are:</em>

<em />

<em>(a) A 99% confidence interval for the actual mean noise level in hospitals is </em><em>(44.02 db, 49.98 db)</em><em>. </em>

For a 99% CI, the value of z is z=2.58

Then, the confidence interval for the mean is:

M-z\sigma/\sqrt{n}\leq\mu\leq M-z\sigma/\sqrt{n}\\\\47-2.58*10/\sqrt{75}  \leq\mu\leq47+2.58*10/\sqrt{75}\\\\47-2.98\leq\mu\leq47+2.98\\\\44.02\leq\mu\leq 49.98

<em>(b) We can be 90% confident that the actual mean noise level in hospitals is </em><em>47 db</em><em> with a margin of error of </em><em>1.89 db</em><em>. </em>

For a 90% CI, the value of z is z=1.64.

Then, we can calculate the margin of error as:

E=z*\sigma/\sqrt{n}=1.64*10/\sqrt{75}=1.89

<em>(c) Unless our sample (of 81 hospitals) is among the most unusual 2% of samples, the actual mean noise level in hospitals is between </em><em>44.41 db and 49.59 db</em><em>. </em>

The 2% tails data corresponds, in the standard normal distirbution, to the values of z whose absolute value is higher than 2.33.

The values of db for these critical values are:

X_1=M+z_1*\sigma/\sqrt{n}=47+(-2.33)*10/\sqrt{81}=47-2.59=44.41\\\\\\ X_2=M+z_2*\sigma/\sqrt{n}=47+(2.33)*10/\sqrt{81}=47+2.59=49.59

3 0
3 years ago
What is five and nine tenths in expanded form?
djyliett [7]
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5 0
3 years ago
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andriy [413]

To find the perimeter we must first find the length of the sides. How to do this is shown below:

The formula for the area of a square is:

A = s²

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Now we must find the length of the side (s). To do this we must get rid of the square. To remove the square from s take the square root of both sides:

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The volume of the cylindrical figure is given by:
V=πr^2h
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Therefore the volume of the cylinder will be:
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3 years ago
What is the mean of 72, 65, 76, 34, 98, 76, 64, 54, and 64.
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2 years ago
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