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Murrr4er [49]
3 years ago
12

the differene between two numbers is 12. eight times the larger number is 20 times the smaller number. write a system of equatio

ns describing the given condition. then solve the system by substitution method and find the two numbers.
Mathematics
1 answer:
VikaD [51]3 years ago
7 0
X - y = 12......x = 12 + y
8x = 20y

8(12 + y) = 20y
96 + 8y = 20y
96 = 20y - 8y
96 = 12y
96/12 = y
8 = y <=== ur smaller number

x - y = 12
x - 8 = 12
x = 12 + 8
x = 20 <== ur larger number
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The problem is attached, thanks.
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Answer:

\displaystyle \frac{dy}{dx} \bigg| \limit_{(1, 4)} = 2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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  • Left to Right

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  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Coordinates (x, y)
  • Exponential Rule [Root Rewrite]:                                                                 \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}
  • Exponential Rule [Rewrite]:                                                                           \displaystyle b^{-m} = \frac{1}{b^m}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Implicit Differentiation

Basic Power Rule:

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Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \sqrt{x} - \sqrt{y} = -1

Point (1, 4)

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                               \displaystyle x^{\frac{1}{2}} - y^{\frac{1}{2}} = -1
  2. [Implicit Differentiation] Basic Power Rule:                                                 \displaystyle \frac{1}{2}x^{\frac{1}{2} - 1} - \frac{1}{2}y^{\frac{1}{2} - 1}\frac{dy}{dx} = 0
  3. [Implicit Differentiation] Simplify Exponents:                                               \displaystyle \frac{1}{2}x^{\frac{-1}{2}} - \frac{1}{2}y^{\frac{-1}{2}}\frac{dy}{dx} = 0
  4. [Implicit Differentiation] Rewrite [Exponential Rule - Rewrite]:                   \displaystyle \frac{1}{2x^{\frac{1}{2}}} - \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0
  5. [Implicit Differentiation] Isolate <em>y</em> terms:                                                       \displaystyle -\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}
  6. [Implicit Differentiation] Isolate \displaystyle \frac{dy}{dx}:                                                               \displaystyle \frac{dy}{dx} = \frac{2y^{\frac{1}{2}}}{2x^{\frac{1}{2}}}
  7. [Implicit Differentiation] Simplify:                                                                 \displaystyle \frac{dy}{dx} = \frac{y^{\frac{1}{2}}}{x^{\frac{1}{2}}}

<u>Step 3: Evaluate</u>

  1. Substitute in point [Derivative]:                                                                     \displaystyle \frac{dy}{dx} = \frac{(4)^{\frac{1}{2}}}{(1)^{\frac{1}{2}}}
  2. Exponents:                                                                                                     \displaystyle \frac{dy}{dx} = \frac{2}{1}
  3. Division:                                                                                                         \displaystyle \frac{dy}{dx} = 2

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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