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3 years ago

The answer is 2sqrt2

Mathematics

1 answer:

vladimir1956 [14]3 years ago

3 0

Answer:

Step-by-step explanation:

The triangle is isosceles. That means that the unmarked side is also x

The Pythagorean Theorem applies

x^2 + x^2 = 4^2

2x^2 = 16 Divide by 2

2x^2/2 = 16/2

x^2 = 8

x^2 = 2 * 2 * 2

sqrt(x^2) = sqrt(2 * 2 * 2)

The rule is take one of a pair of factors out of the root sign and through the other member of the pair away. The third 2 stays under the root sign.

x = 2sqrt(2)

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The square of a certain number is the<br> same as three times the number.<br> What is the number?

Oduvanchick [21]

Answer:

3 x 3 = 9 or 3²=9

Step-by-step explanation:

Multiply both sides by 1/x

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2 years ago

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3 years ago

I don't really understand it's due soon can someone please help me

katrin [286]

Answer:

Step-by-step explanation:

Given: 1/2a + 2/3b =50

(Since b is equal to 30 we will automatically replace b with 30)

Step 1: Simplify both sides of the equation.

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Step 2: Subtract 20 from both sides.

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3 years ago

Read 2 more answers

Solve the following systems by Elimination

Alenkasestr [34]

Answer:

The solutions for both system of equations are as follows:

(5,2)
(2,-1)

Step-by-step explanation:

The first set of equations is:

$4x+6y=32\\3x-6y=3\\$

It can clearly be seen that the coefficients of y are already same in magnitude with different signs so we have to add both equations

So adding both equations, we get

$4x+6y+3x-6y = 32+3\\7x = 35\\\frac{7x}{7} = \frac{35}{7}\\x = 5$

Putting x=5 in equation 1

$4(5)+6y = 32\\20+6y = 32\\6y = 32-20\\6y = 12\\\frac{6y}{6} = \frac{12}{6}\\y = 2$

The solution is (5,2)

The second set of simultaneous equations is:

$-3x+5y=-113x+7y=-1$

We can see that the coefficients of x in both equations are same in magnitude with opposite signs so

Adding both equations

$-3x+5y+3x+7y = -11-1\\12y = -12\\\frac{12y}{12} = \frac{-12}{12}\\y = -1$

Putting y= -1 in first equation

$-3x+5(-1)=-11\\-3x-5=-11\\-3x=-11+5\\-3x=-6\\\frac{-3x}{-3} = \frac{-6}{-3}\\x = 2$

The solution is: (2,-1)

Hence,

The solutions for both system of equations are as follows:

(5,2)
(2,-1)

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