I think that it is 200,000
Answer:
10 buses are needed.
9 buses will only be able to take 468 people.
Explanation:
There are 461 + 20 = 481 people altogether needing transport. Each bus can take at most 52 people. The number of buses needed =
482 ÷ 52.
482 ÷ 52 = 9.25 buses. You might be tempted to round down to 9 buses (because of the 2 that follows the decimal) However, if there are 9 buses,
9 × 52 = 468 people can be taken There will still be
13 people to be transported. This is an example of where you need to round UP to the next whole number.
10 buses are needed. In reality it means that not all the buses will be full, but 10 buses are needed to ensure that everyone gets a ride to the museum.
Solution:
we are given that
6 people can sit together at 1 rectangular table.
2 tables are placed together, 10 people can sit together.
14 people can sit if three tables are put together.
It mean we get a sequence
6,10,14..........
So its making an arithmetic progression, where
First term
Common difference
Number of terms=number of table
As we know the nth term is given by the formula

Hence 402 people can sit.
We are asked to evaluate the limit of (e^-2x)*cosx as x approaches infinity. we can rewrite the equation into cos x / e ^2x. we substitute x with infinity. This is equal to 1/infinity. a number divided by infinity is equal to zero. Hence the answer to this problem is zero