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Marizza181 [45]
2 years ago
5

Find the following in the picture below:

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
3 0

Answer:

ab = 49

abc=253

bac=156

acb=311

Step-by-step explanation:

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What is 2 1/3 + 1 2/3?
SpyIntel [72]
It totals out to 4. I/3 plus 2/3 would equal 1 whole number, then add 1+2+1, you will get 4!
5 0
2 years ago
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-3z+8=2z-12 what is the answer?
Gre4nikov [31]

Answer:

Step-by-step explanation:

Simplifying

-3a + 8 = 2z + -12

Reorder the terms:

8 + -3a = 2z + -12

Reorder the terms:

8 + -3a = -12 + 2z

Solving

8 + -3a = -12 + 2z

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + -3a = -12 + -8 + 2z

Combine like terms: 8 + -8 = 0

0 + -3a = -12 + -8 + 2z

-3a = -12 + -8 + 2z

Combine like terms: -12 + -8 = -20

-3a = -20 + 2z

Divide each side by '-3'.

a = 6.666666667 + -0.6666666667z

Simplifying

a = 6.666666667 + -0.6666666667z

3 0
2 years ago
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Find the probability. Round your answer to the nearest hundredth, if needed.
padilas [110]

Answer:

0.2

Step-by-step explanation:

Given:

Total number of students = 20

Number of students who have brown hair = 12

Number of students who have blonde hair = 4

Number of students who have red hair = 3

Number of students who have black hair = 1

To find:

Probability of randomly selecting a blonde-haired student from the classroom.

Solution:

Probability refers to chances of occurring of some event.

Probability = Number of favourable outcomes/ Total number of outcomes

Number of favourable outcomes ( Number of students who have blonde hair ) = 4

Total number of outcomes = 20

So,

Probability of randomly selecting a blonde haired student from the classroom = \frac{4}{20}=\frac{1}{5}=0.2

5 0
2 years ago
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
Pretty easy math equation I think but I forgot how to solve it look at picture
GrogVix [38]
X = 32 because 100 / 4 is 25, which would make the numerator for x 32
7 0
2 years ago
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