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Kaylis [27]
2 years ago
15

Suppose f '' is continuous on (−[infinity], [infinity])

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
4 0

Answer with Step-by-step explanation:

We are given that a function f(x) is continuous on (-\infty,\infty).

1.f'(-1)=0 and f''(-1)=-7

We have to find information about f.

When f'(-1)=0 and f''(-1)=-7 < 0

Then, function is maximum at x=-1.

Therefore, at x=-1, f has local maximum.

Answer:a)at x=-1 ,f has local maximum.

2.) if f'(4)=0 and f''(4)=0

We know that when f''(x)=0 then test fails  then the function has not maximum or minimum.

Therefore, at x=4 , f has not a maximum or minimum.

Answer:c) at x=4, f has not a maximum or minimum.

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giles is searching for a sock and discovers that he has 10 socks for every 5 pairs of shoes. if he has 20 socks how many pair of
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It will be 10 pair of shoe
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Jada's pet turtle walked 12 feet, and then that length again.
ioda

Answer:

if you are asking in all how many feet he walked the 24ft

Step-by-step explanation:

7 0
3 years ago
The ratio of the measures of the sides of a
ANTONII [103]

Answer:

The length of the sides are 8 , 32 , 36

Step-by-step explanation:

Ratio of sides = 2  : 8 : 9

The sides are 2x , 8x , 9x

Perimeter of triangle = 76 inches

2x+ 8x + 9x  = 76

              19x = 76

                 x = 76/19

x = 4

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6 0
3 years ago
Read 2 more answers
Which of the following sets could be the sides of a right triangle?
coldgirl [10]

Answer: Choice B) {3, 5, sqrt(34)}

=====================================

Explanation:

We can only have a right triangle if and only if a^2+b^2 = c^2 is a true equation. The 'c' is the longest side, aka hypotenuse. The legs 'a' and 'b' can be in any order you want.

-----------

For choice A,

a = 2

b = 3

c = sqrt(10)

So,

a^2+b^2 = 2^2+3^2 = 4+9 = 13

but

c^2 = (sqrt(10))^2 = 10

which is not equal to 13 from above. Cross choice A off the list.

-----------

Checking choice B

a = 3

b = 5

c = sqrt(34)

Square each equation

a^2 = 3^2 = 9

b^2 = 5^2 = 25

c^2 = (sqrt(34))^2 = 34

We can see that

a^2+b^2 = 9+25 = 34

which is exactly equal to c^2 above. This confirms the answer.

-----------

Let's check choice C

a = 5, b = 8, c = 12

a^2 = 25, b^2 = 64, c^2 = 144

So,

a^2+b^2 = c^2

25+64 = 144

89 = 144

which is a false equation allowing us to cross choice C off the list.

7 0
2 years ago
Which of the following shows the extraneous solution(s) to the logarithmic equation? log4 (x) + log4(x - 3) = log4 (-7x + 21)
Salsk061 [2.6K]
First join the log4 on the left:

log4( x*(x-3) = log4(-7x+21)

Then x = -7, works: -7*(-10)=70 = -7*(-7)+21

x=-3, 18 = 42, does not work

x=3 0=0 works,

However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.

Now x=3 gives log4(0) on the left and right, which does not exist.

So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
 
6 0
3 years ago
Read 2 more answers
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