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3 years ago

If a cylinder has a height of 7 inches and a volume of 2908.33 in3 find its diameter

2 answers:

7 0

Heya user

We have over here -

Radius , r= ?

Height , h = 7 inch

Then volume ,= 2πrh

$volume \: \: = 2908.33 \\ \\ 2\pi \: rh \: \: = 2908.33 \\ \\ = > r \: \: = \frac{2908.33}{43.96} \\ \\ = > r \: \: = 64$
So we have Radius 64 approx

so , Diameter , = 128 inch

Makovka662 [10]3 years ago

3 0

The answer should be 23. Not sure if you have multiple choices, or have to show the work, but 23 is the answer.

You might be interested in

Reduce to the lowest terms by canceling -14/9 times -3/7

maksim [4K]

Answer:

2/3

Explanation:

Given the below;

$\frac{-14}{9}\times\frac{(-3)}{7}$

We can see from the above that 9 is divisible by 3 and that 14 is divisible by 7, let's go ahead and reduce to the lowest term as shown below;

$\frac{-14}{9}\times\frac{(-3)}{7}=\frac{-2}{3}\times\frac{(-1)}{1}=\frac{2}{3}$

5 0

10 months ago

A town has a population of 8000 and grows at 3% every year. To the nearest tenth of a year, how long will it be until the popula

Alexxx [7]

Answer:

It will take approximately 34 years

Step-by-step explanation:

If a town population is 8000 and grows 3% annually.

How long will it take to reach 16300

growth is 16300 - 8000 = 8300

using simple interest formula

SI = (P × r × t)/100

8300 = (8000 × 3 × t)100

8300= (80 × 3)t

8300 = 240t

t = 8300/240

t ≈ 34 years to the nearest tenth

8 0

2 years ago

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

3 years ago

It is estimated that each guest at a party will eat 2/3 pounds of chocolate. How many guest can be served with 6 pounds of choco

alexdok [17]

In this you have to do 6(total) /(Divided) 2/3. And when you do 6/(2/3) you also have to do KCF(keep, change, flip) and that brings you to 18/2 after multiplying across. So the answer would be 9 people.

6 0

2 years ago

A cone has a radius that is<br> 12.5cm and a height of 10cm.<br> What is the volume?

Goshia [24]

Answer:

1636.25

Step-by-step explanation:

5 0

2 years ago