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Masteriza [31]
3 years ago
5

Someone knows how to do this? Please, help me!

Mathematics
1 answer:
erica [24]3 years ago
5 0

Answer:

a   K=2

b   A =200

c  B = ±2

Step-by-step explanation:

A = kB^2

When A =50 B=5

Substitute these values in

50 = k * 5^2

50 = k*25

Divide by 25

50/25 = k25/25

2 =k

A = 2B^2


When B = 10

A = 2*10^2

A = 2 *100

A = 200


When A =8

8 =2B^2

Divide by 2

8/2 = 2/2B^2

4 = B^2

Take the square root

±sqrt(4) = sqrt(B^2)

±2 = B

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Please help +25 points
mestny [16]
The answer is D.
Hope I helped
8 0
2 years ago
What is the Laplace Transform of 7t^3 using the definition (and not the shortcut method)
Leokris [45]

Answer:

Step-by-step explanation:

By definition of Laplace transform we have

L{f(t)} = L{{f(t)}}=\int_{0}^{\infty }e^{-st}f(t)dt\\\\Given\\f(t)=7t^{3}\\\\\therefore L[7t^{3}]=\int_{0}^{\infty }e^{-st}7t^{3}dt\\\\

Now to solve the integral on the right hand side we shall use Integration by parts Taking 7t^{3} as first function thus we have

\int_{0}^{\infty }e^{-st}7t^{3}dt=7\int_{0}^{\infty }e^{-st}t^{3}dt\\\\= [t^3\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(3t^2)\int e^{-st}dt]dt\\\\=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\

Again repeating the same procedure we get

=0-\int_{0}^{\infty }\frac{3t^{2}}{-s}e^{-st}dt\\\\=\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt\\\\\int_{0}^{\infty }\frac{3t^{2}}{s}e^{-st}dt= \frac{3}{s}[t^2\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t^2)\int e^{-st}dt]dt\\\\=\frac{3}{s}[0-\int_{0}^{\infty }\frac{2t^{1}}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{2}}[\int_{0}^{\infty }te^{-st}dt]\\\\

Again repeating the same procedure we get

\frac{3\times 2}{s^2}[\int_{0}^{\infty }te^{-st}dt]= \frac{3\times 2}{s^{2}}[t\int e^{-st} ]_{0}^{\infty}-\int_{0}^{\infty }[(t)\int e^{-st}dt]dt\\\\=\frac{3\times 2}{s^2}[0-\int_{0}^{\infty }\frac{1}{-s}e^{-st}dt]\\\\=\frac{3\times 2}{s^{3}}[\int_{0}^{\infty }e^{-st}dt]\\\\

Now solving this integral we have

\int_{0}^{\infty }e^{-st}dt=\frac{1}{-s}[\frac{1}{e^\infty }-\frac{1}{1}]\\\\\int_{0}^{\infty }e^{-st}dt=\frac{1}{s}

Thus we have

L[7t^{3}]=\frac{7\times 3\times 2}{s^4}

where s is any complex parameter

5 0
3 years ago
A glass box shaped like a rectangular prism has width 7 inches, length 9 inches, and height 12 inches. It is being shipped in a
Nadusha1986 [10]

Answer:

744 in³

Step-by-step explanation:

Since you are filling the larger box with both rectangular prism and Styrofoam peanuts, you need to find the overall volume of the larger box and subtract the volume of the glass box to find the amount of space that the Styrofoam peanuts need to take up.  

Volume (prism) = Bh, where B = area of the base, h = height

Larger Box:  V = 10 x 10 x 15 = 1500 in³

Glass Box: V = 7 x 9 x 12 = 756 in³

1500 - 756 = 744 in³ of Styrofoam peanuts

8 0
3 years ago
The ratio of angles angles A:B:C is 5:4:3 . find measure of angle A and B And C
mr Goodwill [35]

Answer:

A=75

B=60

C=45

Step-by-step explanation:

5+4+3=12

every triangle is equal to 180 so we divide

180/12=15

then we multiply each angle by 15

5*15

4*15

and 3*15

don't forget to check your work by adding the answers together to get 180

8 0
3 years ago
The odds in favor of a horse winning a race are 7:4. Find the probability that the horse will win the race.
Sliva [168]

Answer:

7/11 = 0.6363...

Step-by-step explanation:

7 + 4 = 11

probability of winning: 7/11 = 0.6363...

7 0
3 years ago
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