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BARSIC [14]
3 years ago
10

Please can someone solve thiss !!! T~T

Mathematics
2 answers:
Mademuasel [1]3 years ago
8 0

Answer:

y=2x

Step-by-step explanation:

morpeh [17]3 years ago
7 0

Answer:

y=2x

is the answer answer

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How do you simply the square root of 28
maria [59]
\sqrt{28} can be rewritten as ;
=\sqrt{7*4}
=\sqrt{4} * \sqrt{7}
=2\sqrt{7}
3 0
3 years ago
Five times a number is 6 more than two times the number
34kurt

Answer:

5x= 2x+6

Step-by-step explanation:

5 times a number= 5x

2 times the number=2x

6 more= +6

7 0
3 years ago
Read 2 more answers
A drawing of a new car uses a scale of 4 inches = 5 feet. The drawing of the car is 10 inches long. How long is the car?
Naddika [18.5K]

Answer:

The car is 10 feet and 5 inches.

Step-by-step explanation:

First you must know how many times 4 goes into 10 because that's how long the picture is. 10 divided by 4 is 2.5. This means that 4 goes into 10 4.5 times meaning that there's a measure of 10 feet with a remaining 5 inches.

4 0
3 years ago
Work out the volume of the cone, giving your answer<br> to 3 significant figures.
Aliun [14]

Answer: 1010

Step-by-step explanation:

V=\frac{1}{3}(\pi)(8^{2})(15) \approx \boxed{\text{ } 1010 \text{ cm}^{3}}

6 0
2 years ago
Solve this equation using all three methods 4x^ = 9
Bumek [7]

Answer:

x=-\frac{3}{2}, x=\frac{3}{2}

Step-by-step explanation:

(1)       To solve by factoring,

Given equation: 4 x^{2}=9

Subtract 9 from both sides of the equation.

\begin{aligned}&4 x^{2}-9=9-9\\&4 x^{2}-9=0\\&(2 x)^{2}-3^{2}=0\\&(2 x-3)(2 x+3)=0\end{aligned}

Using zero factor principle, 2 x-3=0,2 x+3=0

The solutions are x=-\frac{3}{2}, x=\frac{3}{2}.

(2) To solve by complete the square ,

Given 4 x^{2}=9

Divide both sides of the equation by 4.  

\frac{4 x^{2}}{4}=\frac{9}{4}  

\Rightarrow x^{2}=\frac{9}{4}  

Square root on both sides.

$\Rightarrow x=\pm \frac{3}{2}$

x=-\frac{3}{2}, x=\frac{3}{2}

(3) To solve by quadratic formula,  

$4 x^{2}-9=0$

Here, a = 4, b = 0, c = –9

Quadratic formula, $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

x=\frac{-0 \pm \sqrt{0^{2}-4 \times 4 \times(-9)}}{2 \times 4}

\begin{aligned}&\Rightarrow x=\frac{\pm \sqrt{144}}{8}\\&\Rightarrow x=\pm \frac{3}{2}\\&\Rightarrow x=\frac{3}{2}, x=-\frac{3}{2}\end{aligned}

3 0
3 years ago
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