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kenny6666 [7]
3 years ago
11

A plant can produce either purple flowers or white flowers. What is the probability of purple-flowered offspring if two plants t

hat are heterozygous for purple flowers are crossed?
1:4

2:4

3:4

4:4
Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
6 0

Answer: C) 3:4

Step-by-step explanation:

tankabanditka [31]3 years ago
3 0

When there are two options of the type of flower: either purple or white, the  probability of purple-flowered offspring if two plants that are heterozygous for purple flowers are crossed is 3:4. Hence the answer to this problem is option C. 3:4. 
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Using it's concept, considering the number of desired and total outcomes, it is found that the probabilities are given by:

a. 0.6 = 60%.

b. 0.4 = 40%.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In an experimental probability, these numbers of outcomes are taken from previous trials.

Researching the problem on the internet, it is found that there is a total of 127 + 44 + 95 + 104 = 370 customers.

Item a:

127 + 95 = 222 customers prefer either baked potato or asparagus, hence the probability is given by:

p = 222/370 = 0.6 = 60%.

Item b:

44 + 104 = 148 customers prefer either steamed broccoli or sweet potato, hence the probability is given by:

p = 148/370 = 0.4 = 40%.

More can be learned about probabilities at brainly.com/question/14398287

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When flipping a coin three times, what is the probability of landing on tails all two times?
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I believe it is A or B
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Select the inequality represented by the graph.
dimaraw [331]

Answer:

what graph?

Step-by-step explanation:

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3 years ago
A, B, and C are pegs on the bank of a canal which has
Elden [556K]

Answer:

116.67 m

Step-by-step explanation:

Two triangles are said to be similar if their corresponding angles are equal and the ratio of their sides are in the same proportion.

From the image attached:

∠A = ∠C = 90° (right angled triangle).

∠ABE = ∠CBD (vertically opposite angles are equal to each other)

The angle-angle similarity postulate states that If two angles of one triangle are equal to two angles of another triangle, then both triangles must be similar. Hence:

Since, ∠A = ∠C and ∠ABE = ∠CBD, we can say that ΔABE and ΔCBD are similar triangles. Since they are similar, the ratio of their corresponding sides is equal. Therefore:

BC / AB = CD / AE

BC = 140 m, AB = 30 m, AE = 25 m

substituting:

140 / 30 = CD / 25

CD = (140 / 30) * 25

CD = 116.67 m

The width of the canal = CD = 116.67 m

7 0
3 years ago
In October 1947, the Gallup organization surveyed 1100 adult Americans and asked "Are you a total abstainer from, or do you on o
Rasek [7]

Answer:

z=\frac{0.37-0.303}{\sqrt{0.336(1-0.336)(\frac{1}{1100}+\frac{1}{1100})}}=3.327 .  

p_v =2*P(Z>3.327)= 0.000878    

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportions for this case are different so then there is enough evidence to conlcude that the real proportion change.

Step-by-step explanation:

Information provided

X_{1}=407 represent the number of people who answer abstainers in 1947

X_{2}=333 represent the number of people who answer abstainer recnetly

n_{1}=1100 sample 1 selected  

n_{2}=1100 sample 2 selected  

p_{1}=\frac{407}{1100}=0.37 represent the proportion estimated of people who answer abstainers in 1947

p_{2}=\frac{333}{1100}=0.303 represent the proportion estimated of people who answer abstainers recently

\hat p represent the pooled estimate of p

z would represent the statistic

p_v represent the p value

\alpha=0.05 significance level given  

Hypothesis to test

We want to verify if the proportion of adult Americans who totally abstain from alcohol changed , the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{407+333}{1100+1100}=0.336  

Replacing the info given we got:    

z=\frac{0.37-0.303}{\sqrt{0.336(1-0.336)(\frac{1}{1100}+\frac{1}{1100})}}=3.327    

p_v =2*P(Z>3.327)= 0.000878    

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true proportions for this case are different so then there is enough evidence to conlcude that the real proportion change.

6 0
3 years ago
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