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4 years ago

14

How to solve a broblem

1 answer:

omeli [17]4 years ago

6 0

Answer:

You can solve a problem. by evaluating the situation and determinig which stragey is fit for use what ever you prefer.

You might be interested in

irina1246 [14]

Answer:

$13,392

Step-by-step explanation:

it will cost that because 1240 times 10.8 = 13,392

8 0

3 years ago

The table below shows a pattern in the cost of renting a car based on the number of days rented. Car Rentals Number of Days (d)

andrezito [222]

The linear equation that describes the pattern in the cost of renting a car is given by:

D. c = 34d + 25

<h3>What is a linear function? </h3>

A linear function is modeled by:

$y(x) = mx + b$

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0.

In this problem:

For each day, the cost of renting a car increases by 34, hence, the slope is of 34, and the equation is:

$c(d) = 34d + b$

When d = 4, c = 161, and this is used to find b.

$c(d) = 34d + b$

$161 = 34(4) + b$

$b = 25$

Hence, the equation is c = 34d + 25, and option D is correct.

You can learn more about linear functions at brainly.com/question/25823744

6 0

3 years ago

The sum of two numbers is 17 and their difference is 5 what are the two answers

MrRa [10]

Answer:

Transforms

Step-by-step explanation:

Transforms

4 0

3 years ago

Find the coefficients of the terms below in the expansion of (uu+vv)8. Explain your reasoning.

gladu [14]

Answer:

Remember, the expansion of $(u+v)^n=\sum_{k=0}^n\binom{n}{k}u^{n-k}v^k$ .

Then,

$(u+v)^8=\sum_{k=0}^8\binom{8}{k}u^{8-k}v^k$

a) since $u^{8-k}=u^2$ , then $8-k=2, k=6$ . Therefore, the coefficient of $u^2v^6$ is $\binom{8}{6}=28$

b) $u^3v^5=u^{8-k}v^k$ . Then k=5 and the coefficient of the term is $\binom{8}{5}=56$

c) $u^4v^4$ , then k=4 and the coefficient of the term is $\binom{8}{4}=70$

8 0

3 years ago

This is algebra 2. Would like an answer ASAP. Thanks! Between the two chunks of numbers, thats a division sign, not an addition

NeX [460]

Answer:

Simplified form of $\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$ is $\mathbf{\frac{1}{(x+3)(x+4)} }$

Option A is correct answer.

Step-by-step explanation:

We need to find simplified form of $\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$

Solving the given expression:

$\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$

First we find factors of $x^2+x-6$

$x^2+x-6 \\= x^2+3x-2x-6\\= x(x+3)-2(x+3)\\=(x-2)(x+3)$

So, factors of $x^2+x-6$ are $(x-2)(x+3)$

Now, fining the factors of $x^2+5x+4$

$x^2+5x+4\\=x^2+4x+x+4\\=x(x+4)+1(x+4)\\=(x+1)(x+4)$

So, factors of $x^2+5x+4$ are $(x+1)(x+4)\\$

Now the given expression will become:

$\frac{x+1}{(x-2)(x+3)}\div \frac{(x+1)(x+4)}{x-2}$

Now, converting division sign into multiplication sign:

$=\frac{x+1}{(x-2)(x+3)}\times \frac{x-2} {(x+1)(x+4)}\\Cancelling, \:common\:terms\\=\frac{1}{(x+3)(x+4)}$

So, simplified form of $\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$ is $\mathbf{\frac{1}{(x+3)(x+4)} }$

Option A is correct answer.

4 0

3 years ago