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rosijanka [135]
3 years ago
10

Please help me!thank u <3

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
4 0

Answer:

x = 15

LM = 18

MN = 18

LN = 18

Step-by-step explanation:

To find x:

x + 3 + 2x - 12 + 33 - x = 54

2x + 24 = 54

2x = 54 - 24

2x = 30

x = 15

LM:

x + 3

15 + 3

18

MN:

33 - x

33 - 15

18

LN:

2x - 12

2(15) - 12

30 - 12

18

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MATH HELP PLZ!!!
RoseWind [281]

Answer:

a)    tan (157.5) = \frac{1-cos 315}{sin315}

b)

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c)

      sin^{2} (157.5) = \frac{1-cos (315) }{2}

d)

  cos 330° = 1- 2 sin² (165°)

       

         

Step-by-step explanation:

<u><em>Step(i):-</em></u>

By using trigonometry formulas

a)

cos2∝  = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ =  2 cos² ∝/2

cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}

b)

cos2∝  = 1- 2 sin² ∝

cos∝  = 1- 2 sin² ∝/2

sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

<u><em>Step(i):-</em></u>

Given

              tan\alpha = \frac{sin\alpha }{cos\alpha }

          we know that trigonometry formulas

        sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

         1- cos∝ =  2 sin² ∝/2

      Given

         tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }

put ∝ = 315

      tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }

     multiply with ' 2 sin (∝/2) both numerator and denominator

        tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2}  }{2sin(\frac{315}{2} cos(\frac{315}{2}) }

Apply formulas

 sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

  1- cos∝ =  2 sin² ∝/2

now we get

 tan (157.5) = \frac{1-cos 315}{sin315}

       

b)

          sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 330° above formula

             sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}

            sin^{2} (165) = \frac{1-cos (330) }{2}

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c )

         sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 315° above formula

             sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}

            sin^{2} (157.5) = \frac{1-cos (315) }{2}

           

d)

     cos∝  = 1- 2 sin² ∝/2

   put      ∝ = 330°

       cos 330 = 1 - 2sin^{2} (\frac{330}{2} )

      cos 330° = 1- 2 sin² (165°)

3 0
3 years ago
Each vertex of a quadrilateral is dilated by a factor of 2 about the point Al-4, 7). What will be the effect on the perimeter of
Serggg [28]
The perimeter will increase by 2 units
5 0
2 years ago
What solution is <br> y=9x+35<br> y=-8/9x+4/5
Ainat [17]

Answer:

x=-1539/445, y=1724/445. (-1539/445, 1724/445).

Step-by-step explanation:

y=9x+35

y=-8/9x+4/5

-------------------

9x+35=-8/9x+4/5

9x-(-8/9x)=4/5-35

9x+8/9x=4/5-175/5

81/9x+8/9x=-171/5

89/9x=-171/5

x=(-171/5)/(89/9)

x=(-171/5)(9/89)

x=-1539/445

y=9(-1539/445)+35

y=1724/445

6 0
3 years ago
Antonio earned the following points during a game:4.26 points, -3 and one half points, and 7 over 10 points. What is the final s
KiRa [710]

1.46 points put them all in to decimals so 4.26-3.5= .76 + .7 is 1.46

3 0
3 years ago
Which graph represents the solution set of the inequality Negative 9 greater-than x?
Kamila [148]

Answer:

de answer is A

Step-by-step explanation:

hope i helped

7 0
4 years ago
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