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Anon25 [30]
4 years ago
13

Find the area of shaded part .​

Mathematics
1 answer:
Firlakuza [10]4 years ago
5 0

Answer:

Area of big rectangle= 5m× 3m

                                   = 15m²

Area of small rectangle=1m× 1m

                                       =1m²

Area of shaded part= Area of big rectangle- Area of a small rectangle

                                 = 15m²-1m²

                                  = 14m²

Step-by-step explanation: Hope it helps

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Out of 290 racers who started the marathon, 272 completed the race, 15 gave up, and 3 were disqualified. What percentage did not
jeka57 [31]

Answer:

6% of the racers did not ocmplete the marathon

Step-by-step explanation:

290 racers

272 completed the race

15 + 3 = 18 did not complete the race

\frac{272}{290} = 0.94 = 94%

\frac{18}{290} = 0.06 = 6%

7 0
3 years ago
"mon ame ne suivit pas la sienne"<br><br><br>quelle figure de style represente cette phrase?​
just olya [345]

Answer:

It is a metaphor.

Step-by-step explanation:

Hope it helps

3 0
3 years ago
Possible side lengths for a rectangular frame are 6 inches, 10 inches, and 12 inches
alexdok [17]

Answer:

A

Step-by-step explanation:

You have to times all of them to see the results. For example...

A. 48inches(6x8), 50inches(5x10), 48inches(12x4)

B. 42,50,48(42 is not within 45-50 inches so it can't be B)

C.48,40,48(40 is not within 45-50 inches so it can't be C)

D.42,48,50,48(42 is not within 45-50 inches so it can't be D)

meaning it's A

3 0
3 years ago
The circumference of a circle is 9.45cm.
Fudgin [204]

Answer:

D = 3 cm

Step-by-step explanation:

Given that,

The circumference of a circle is 9.45cm.

We need to find the length of the diameter.

The formula for the circumference of a circle is given by :

C=2\pi r

We know that, Diameter = 2r

So,

C=D\pi\\\\D=\dfrac{C}{\pi}\\\\D=\dfrac{9.45}{\pi}\\\\D=3\ cm

So, the length of diameter is equal to 3 cm.

8 0
3 years ago
Pls help!! Find the area of the lighter shaded region and round to the nearest tenth.
Elenna [48]

Answer:

5.1 cm² approximately

Step-by-step explanation:

A lighter= Area inscribed -1/2r² sin80°

A lighter=π r² (80°/360°) -1/2(5 cm)² sin 80°

A lighter=π(5cm)² (80°/360°) -1/2(5 cm)² sin 80°

A lighter=3.14*25cm²(80°/360°) - 12.5cm² sin 80°

A lighter=17.444…cm² - 12.31009... cm²

A lighter=5.13cm² approximately

3 0
4 years ago
Read 2 more answers
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