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Serhud [2]
3 years ago
13

Please help!! Thank you!!

Physics
1 answer:
ratelena [41]3 years ago
4 0
Spring tides occur<span> twice each lunar month all year long without regard to the season. </span>Neap tides<span>, which also </span>occur<span> twice a month, </span>happen<span> when the sun and moon are at right angles to each other.</span>
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Find the network done by friction on a box that moves in a complete circle of radius 1.82 m on a uniform horizontal floor. The c
m_a_m_a [10]

Answer:

C) W = - 190 J

Explanation:

Notation

Wf = work done by the friction force (unknown)

Ff = force of the friction

d = distance travelled by the box = (2 pi 1.82 m) = 11.435 m

6 0
3 years ago
Read 2 more answers
How are mass and free fall related to acceleration?
Likurg_2 [28]

Answer:

Increasing force tends to increase acceleration while increasing mass tends to decrease acceleration. Thus, the greater force on more massive objects is offset by the inverse influence of greater mass. Subsequently, all objects free fall at the same rate of acceleration, regardless of their mass.

Explanation:

It let me answer now

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6 0
3 years ago
The speed of a box traveling on a horizontal friction surface changes from vi = 13 m/s to vf = 11.5 m/s in a distance of d = 8.5
KiRa [710]

Answer:

0.68 s

Explanation:

We are given that

Initial velocity of box=u=13m/s

Final velocity of box=v=11.5 m/s

Distance=d=8.5 m

We have to find the time taken by box to slow by this amount.

We know that

v^2-u^2=2as

Substitute the values

(11.5)^2-(13)^2=2a(8.5)

132.25-169=17a

-36.75=17a

a=\frac{-36.75}{17}=-2.2m/s^2

We know that

Acceleration=a=\frac{v-u}{t}

Substitute the values

-2.2=\frac{11.5-13}{t}

-2.2=\frac{-1.5}{t}

t=\frac{1.5}{2.2}=0.68 s

Hence, the time taken by box to slow by this amount=0.68 s

8 0
4 years ago
Which of the following are pure substances
Lilit [14]
We’re are the answer choice at ?
7 0
3 years ago
3. What is the main difference between a physical change and a chemical
Lana71 [14]

Answer:

B and D could both be right as they are quit similar.

Consider two rods of the same length and diameter,

Increasing the diameter of one would change the expansion qualities of that rod even though there would be no chemical changes,

However, leaving the physical appearance of both rods the same while applying a reactive substance (acid or something) to one of the rods would not necessarily change the physical appearance of that rod but could make a considerable change in the  physical properties of that rod.

3 0
4 years ago
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