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3 years ago

10

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1 answer:

Sergio [31]3 years ago

4 0

Answer:No

Step-by-step explanation:

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kirza4 [7]

Answer:

50

Step-by-step explanation:

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2 years ago

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Write the verbal sentence as an equation or an inequality: Four is greater than six times a number t. really need help can't rea

maw [93]

4 > 6*t

Number t refers to an unknown. In this case, t can only be 0, because 6*0 = 0, and 4 > 0 or four is greater than 0.

5 0

2 years ago

⦁ Write an equation of a line in slope intercept form (y = mx + b) with slope 1/3 going through the point (-6, 2). Show your wor

Zepler [3.9K]

$(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-6)}) \\\\\\ y-2=\cfrac{1}{3}(x+6)\implies y-2=\cfrac{1}{3}x+2\implies y=\cfrac{1}{3}x+4$

3 0

1 year ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Which expression can be used to approximate the expression below, for all positive numbers a, b, and x, where a Not-equals 1 and

defon

The expression that can be used to approximate the expression below is $log_a x = \frac{log_{b}a}{log_{b}x}$

Given the logarithmic function expressed as $log_a x$ , we need the log expression that is equivalent to the given expression.

To do this, we will write the logarithm as a quotient to the same base. Using the base of 10, the expression can be written as;

$log_a x = \frac{log_{10}a}{log_{10}x}$

This is similar to the option c where the base of "b" was used as $log_a x = \frac{log_{b}a}{log_{b}x}$

Learn more on law of logarithms here: brainly.com/question/11587706

3 0

2 years ago