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KengaRu [80]
3 years ago
10

60731903239__8DEE49CD-5BBC-40E2-A8F5-59B32FE3879C.jpeg

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:No

Step-by-step explanation:

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Find the average value of the function f(t)=cos13(5t)sin(5t) f(t)=cos13⁡(5t)sin⁡(5t) on the interval [4,10].
Vilka [71]
The average value is given by

\displaystyle\frac1{10-4}\int_4^{10}\cos^{13}5t\sin5t\,\mathrm dt

Setting y=\cos5t, you get \mathrm dy=-5\sin5t\,\mathrm dt, and the integral becomes

\displaystyle-\frac1{30}\int_{\cos20}^{\cos50}y^{13}\,\mathrm dy
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6 0
3 years ago
Its super duper easy but im having some trouble<br> so can someone help me?
Klio2033 [76]

together = add

add the fractions

3 7/10 + 5 9/10

add the whole numbers first

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8 8/5

whole number changes to 9

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denominator stays the same

9 3/5

Answer:

9 3/5

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Step-by-step explanation:

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Step-by-step explanation:

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