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harina [27]
3 years ago
5

an equation has a slope of -14 and passes through the point, (1,0) what is the slope of the equation of the line when written in

slope-intercept form
Mathematics
2 answers:
Verdich [7]3 years ago
5 0

Answer:

y= -14x +14

Step-by-step explanation:

IrinaK [193]3 years ago
4 0

Answer:

y= -14x +14

Step-by-step explanation:

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SOLVE THIS QUESTION WITH FULL STEPS...THANKS
GalinKa [24]

Answer: which question

Step-by-step explanation:

5 0
3 years ago
Compare and contrast expressions equations and inequalities
babymother [125]
Equations can have one solution, but inequalities have infinite solutions.

Hope this helps!
4 0
3 years ago
Which equation has only 1 solution? A. c+2=c+2 B. c= -c+2 C. c+2=c-2 D. c-c=2 Please explain.
zhannawk [14.2K]

Answer:

B. c= -c+2

Step-by-step explanation:

A. ...................

  • c+2=c+2
  • c-c= 2-2
  • 0=0

It has infinitely many solutions as the equation is correct for any value of c.

B. ...................

  • c= -c+2
  • c+c= 2
  • 2c = 2
  • c = 2/2
  • c= 1

It has one solution only

C. ...................

  • c+2=c-2
  • c-c= -2 - 2
  • 0 = -4

It has no solution as this equation is incorrect

D. ...................

  • c-c=2
  • 0 = 2

It has no solution as this equation is incorrect

6 0
3 years ago
Find the distance between the points -18 and -42. Show your work for full credit. (2 points.)
Masja [62]

Answer:

-24

Step-by-step explanation:

Easy way: 42 - 18 = 24, then translate it to negative 24 because your numbers are negative.

A little bit harder way: -42 + (-18) or -42 + 18 = -24

5 0
3 years ago
Can anyone please help me with this ?
djverab [1.8K]

Answer:

The distance from point A to the top of the building is 5\sqrt{2} feet

The Height of the Skyscraper is 5 feet

Step-by-step explanation:

Given

Let Top point of building be point C

Also Let Base of the building be point  B

Distance from point A to base B of the building AB= 5 feet

∴ It makes a Right angle triangle

Also ∠ACB = 45°

Also tan 45° = 1

Now tan ∠ACB =\frac{AB}{BC}

∴ AB= BC =5 feet

The Height of the Skyscraper is 5 feet

Now Triangle ABC is right angle triangle with right angled at B

So by Pythagoras theorem

AC= \sqrt{AB^2+BC^2}=\sqrt{5^2+5^2} =\sqrt{50} =\sqrt{25\times2} =\sqrt{5^2\times2}=5\sqrt{2}

The distance from point A to the top of the building is 5\sqrt{2} feet

5 0
3 years ago
Read 2 more answers
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