Answer:
a) 301.6 cm³
b) 188.5 cm²
Step-by-step explanation:
The volume and lateral surface area of the cone can be found using the given dimensions with the given formulas. All that is needed is to substitute the appropriate values and do the arithmetic.
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<h3>a) volume</h3>
The volume is given by the formula ...
V = 1/3πr²h
The dimensions are given on the diagram: r = 6 cm, h = 8 cm. Using these values in the formula, we find the volume to be ...
V = 1/3π(6 cm)²(8 cm) = 96π cm³ ≈ 301.6 cm³
The volume of the cone is about 301.6 cm³.
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<h3>b) area</h3>
The lateral area of the cone is given by the formula ...
A = πrl
The dimensions are given on the diagram: r = 6 cm, l = 10 cm (the slant height). Using these values in the formula, we find the area to be ...
A = π(6 cm)(10 cm) = 60π cm² ≈ 188.5 cm²
The area of the curved surface is about 188.5 cm².
Answer:
The Check that hasn't been cleared yet is for $372.15.
Step-by-step explanation:
168.48+ 168.93+ 177.78+ 177.93= 693.12
887.79- 693.12= 194.67
1,065.27- 887.79= 177.48
194.67+ 177.48= 372.15
To check your answer:
372.15+ 693.12= 1,065.27
Hope this helped you!! (:
Hello,
Area under the curve is 1.
So p(x>5)=1-p(x<5)=1-0.0625=0.9375
Answer A
Answer:
A person must get an IQ score of at least 138.885 to qualify.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 115, \sigma = 17](https://tex.z-dn.net/?f=%5Cmu%20%3D%20115%2C%20%5Csigma%20%3D%2017)
(a). [7pts] What IQ score must a person get to qualify
Top 8%, so at least the 100-8 = 92th percentile.
Scores of X and higher, in which X is found when Z has a pvalue of 0.92. So X when Z = 1.405.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.405 = \frac{X - 115}{17}](https://tex.z-dn.net/?f=1.405%20%3D%20%5Cfrac%7BX%20-%20115%7D%7B17%7D)
![X - 115 = 17*1.405](https://tex.z-dn.net/?f=X%20-%20115%20%3D%2017%2A1.405)
![X = 138.885](https://tex.z-dn.net/?f=X%20%3D%20138.885)
A person must get an IQ score of at least 138.885 to qualify.
Answer:
Step-by-step explanation:
Comment
The shape consists of a rectangle on the bottom and a trapezoid on the top.
Rectangle
A rectangle has a very simple Area formula. It is Area = L*W. In this case the L = 14 m and is horizontal. The width is at right angles to the length and is marked as 3.
Area = L * w
L = 14
w = 3
Area = 14 * 3 = 42 m^2
Trapezoid
The trapezoid is a bit more complicated and some things have to be found. First of all b1 is the first base of the trapezoid. It is parallel to and equal to the Length of the rectangle. b2 is marked 10 meters. The height is just a bit more complicated. The total height of the figure is 8 m. You can't count the 3 m of the rectangle as part of the height because b1 comes only to the top of the rectangle. The height is 8 - 3 = 5
Area = 1/2(b1 + b2)*h/2
b1 = 14
b2 = 10
h = 8 - 3 = 5
Area = 1/2 ( 14 + 10) * 5 / 2
Area = 1/2 (24)*5
Area = 12 * 5
Area = <u> 60 m^2</u>
Total Area 102 m^2