All categories

2 years ago

What fraction of 56 of 21?

Mathematics

2 answers:

Paraphin [41]2 years ago

8 0

Seventeen over seven

11111nata11111 [884]2 years ago

7 0

The correct answer is= 3/8

You might be interested in

The combined height of one for tree and one pine tree is 21 meters. The height of 4 for trees stacked on top of each other is 24

slamgirl [31]

Answer:

The height of the fir tree is 9 meters tall and the pine tree is 12 meters.

Step-by-step explanation:

Given:

Note :→ there is a mistake it is fir tree not for tree.

The combined height of one fir tree and one pine tree is 21 meters.

The height of 4 fir trees stacked on top of each other is 24 meters taller than one pine tree.

Now, to find how tall are the types of trees.

Let the height of one fir tree be $x$ .

And the height of one pine tree be $y$ .

So, the combined height of one fir tree and one pine tree:

$x+y=21.$

$y=21-x.$ .........( 1 )

Now, as given the height of 4 for trees stacked on top of each other is 24 meters taller than one pine tree:

$4x=y+24.$

Putting the value of equation (1) in the place of $y$ :

$4x=21-x+24$

Adding both the sides $x$ we get:

$5x=21+24.$

$5x=45.$

Dividing both the sides by 5 we get:

$x=9\ meters.$

So, the height of one fir tree = 9 meters.

Now, putting the value of $x$ in equation (1) we get:

$y=21-9$

$y=12\ meters.$

Thus, the height of one pine tree = 12 meters.

Therefore, the fir tree is 9 meters tall and the pine tree is 12 meters tall.

6 0

2 years ago

Prove the function f: R- {1} to R- {1} defined by f(x) = ((x+1)/(x-1))^3 is bijective.

Eduardwww [97]

Answer:

See explaination

Step-by-step explanation:

given f:R-\left \{ 1 \right \}\rightarrow R-\left \{ 1 \right \} defined by f(x)=\left ( \frac{x+1}{x-1} \right )^{3}

let f(x)=f(y)

\left ( \frac{x+1}{x-1} \right )^{3}=\left ( \frac{y+1}{y-1} \right )^{3}

taking cube roots on both sides , we get

\frac{x+1}{x-1} = \frac{y+1}{y-1}

\Rightarrow (x+1)(y-1)=(x-1)(y+1)

\Rightarrow xy-x+y-1=xy+x-y-1

\Rightarrow -x+y=x-y

\Rightarrow x+x=y+y

\Rightarrow 2x=2y

\Rightarrow x=y

Hence f is one - one

let y\in R, such that f(x)=\left ( \frac{x+1}{x-1} \right )^{3}=y

\Rightarrow \frac{x+1}{x-1} =\sqrt[3]{y}

\Rightarrow x+1=\sqrt[3]{y}\left ( x-1 \right )

\Rightarrow x+1=\sqrt[3]{y} x- \sqrt[3]{y}

\Rightarrow \sqrt[3]{y} x-x=1+ \sqrt[3]{y}

\Rightarrow x\left ( \sqrt[3]{y} -1 \right ) =1+ \sqrt[3]{y}

\Rightarrow x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

for every y\in R-\left \{ 1 \right \}\exists x\in R-\left \{ 1 \right \} such that x=\frac{\sqrt[3]{y}+1}{\sqrt[3]{y}-1}

Hence f is onto

since f is both one -one and onto so it is a bijective

8 0

3 years ago

Evaluate the problem 3.14(6 × 4 + 6^2)

diamong [38]

Answer:

188.4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

APUG: P(1, -3), U(1, 1) and GC-3, 1). A dilation with a scale factor of 2 centered

Novay_Z [31]

Answer:

Step-by-step explanation:

4 0

3 years ago

Determine if each graph below represents a function. Then state its domain and range.

Bas_tet [7]

Answer: None of those are functions

Step-by-step explanation: They all fail the vertical line test. x values do not repeat. Those intersect more than one pint on the relationship if you were to take a line and move it across the graph.

5 0

3 years ago