Answer:
The real roots are
and 
The sum of the squares of these roots is 
Step-by-step explanation:
The given quadratic equation is
has two real roots.
To find the roots .

Dividing the above equation by 2


For quadratic equation
the solution is 
Where a and b are coefficents of
and x respectively, c is a constant.
For given quadratic equation
a=4, b=6, c=-7









The real roots are
and 
Now to find the sum of the squares of these roots
![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%2B%5Csqrt%7B37%7D-3-%5Csqrt%7B37%7D%7D%7B4%7D)


![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%7D%7B2%7D)
Therefore the sum of the squares of these roots is 
Given that the number next to the right of the tenth digit is smaller than 5, it does not change.
Answer: 37.8
RS + ST = RT
3x + 1 + 2x - 2 = 64
5x - 1 = 64
5x = 64 + 1
5x = 65
x = 65/5
x = 13 <==